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3 years ago

11

Beth pays a total of $20 to rent skates and go ice skating for 2 hours.

1 answer:

-Dominant- [34]3 years ago

3 0

Answer:

for 2 hours of skating it will be 12$

Step-by-step explanation:

6+6=12 . (:

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oksian1 [2.3K]

Idek i need points man

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3 years ago

What is the solution to log (9x)-log 3 = 3?

xeze [42]

Answer:

The solution x = $\frac{e^{3} }{3}$

Step-by-step explanation:

<u>Step 1</u>:-

Given $log(9 x) -log 3 =3$

we have to use formula $log a-log b=log\frac{a}{b}$

$log(9 x)- log 3 = log(\frac{9 x}{3} )$ = $3$

Again by using formula $log a =b$

$a = e^{b}$

so $\frac{9 x}{3} =e^{3}$

<u>step 2:</u>-

$3 x = e^{3}$

$x = \frac{e^{3} }{3}$

The solution of given problem is $x=\frac{e^3}{3}$

5 0

3 years ago

Which statement is true about the rectangles shown? They have the same area and perimeter. They have the same perimeter but diff

pishuonlain [190]

Answer:

They have the same perimeter but different areas.

Step-by-step explanation:

7x4 is 28, and 9x2 is 18

But 7+7+4+4 is 22 and 9+9+2+2 is also 22

4 0

3 years ago

A small metal bar, whose initial temperature was 10° C, is dropped into a large container of boiling water. How long will it tak

IgorC [24]

Answer

According to newton law of cooling

$\dfrac{d T}{dt} = k (T - T_a)$

and

$T = Ce^{kt} + T_a$

now At Ta = 100

T₀ = 10 °C

T₁ = 12° C

$T(0) = Ce^{0} + T_a$

10 = C + 100

C = -90

now,

$12 = -90e^k + 100$

$e^k = \dfrac{88}{90}$

$k = ln{\dfrac{88}{90}}$

at time equal to t

T(t) = 70

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$70 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{3}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{3})$

t = 48.88 s

hence, after 48.88 s the temperature of the body will be 70°C

b) time taken to reach 98°C

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$98 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{45}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{45})$

t = 390 s

hence, after 390 s the temperature of the body will be 98°C

5 0

3 years ago

Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger

Andre45 [30]

Answer:

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

Step-by-step explanation:

Let the three consecutive odd integers be: $x-2,x\ and \ x+2$

The condition given is:

$4[x-2+x+x+2]=3x(x+2)-765$

Solve this for <em>x</em> as follows:

$4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0$

If $(x-17)=0$ then the value of <em>x</em> is 17.

The odd numbers are:

$x-2=17-2=15\\x=17\\x+2=17+2=19$

If $(x+15)=0$ then the value of <em>x</em> is -15.

The odd numbers are:

$x-2=-15-2=-17\\x=-15\\x+2=-15+2=-13$

Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

7 0

3 years ago