All categories

2 years ago

given a geomatric progression 2,6,18,54... find the smallest value of n such that the nth term is greater than 100000

Mathematics

1 answer:

stiks02 [169]2 years ago

6 0

Answer:

hello,

Step-by-step explanation:

$u_1=2=2*3^0\\u_2=6=2*3^1\\u_3=18=2*3^2\\u_4=54=2*3^3\\\\....\\u_n=2*3^{n-1}\geq 100000\\\\3^{n-1}\geq 50000\\\\(n-1)*ln(3)\geq ln(50000)\\\\n-1\geq 9,848586...\\\\n\geq 10.848586....\\\\\boxed{n=11}\\$

You might be interested in

According to a survey, 65% of murders committed last year were cleared by arrest or exceptional means. Fifty murders committed

monitta

Answer:

a) $P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421$

b) $P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714$

$P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502$

$P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319$

And adding these values we got:

$P(36 \leq X \leq 38)= 0.1535$

c) We can find the expected value given by:

$E(X) = np =50*0.65 = 32.5$

And the standard deviation would be:

$\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373$

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

$\mu -2\sigma = 32.5- 2*3.373 = 25.75$

And then we can consider a value of 18 as unusual lower for this case.

Step-by-step explanation:

Let X the random variable of interest "number cleared by arrest or exceptional", on this case we can model this variable with this distribution:

$X \sim Binom(n=50, p=0.65)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

We want this probability:

$P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421$

Part b

We want this probability:

$P(36 \leq X \leq 38)$

We can find the individual probabilities:

$P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714$

$P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502$

$P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319$

And adding these values we got:

$P(36 \leq X \leq 38)= 0.1535$

Part c

We can find the expected value given by:

$E(X) = np =50*0.65 = 32.5$

And the standard deviation would be:

$\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373$

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

$\mu -2\sigma = 32.5- 2*3.373 = 25.75$

And then we can consider a value of 18 as unusual lower for this case.

6 0

3 years ago

Im very confused. I need help. Asap.

masya89 [10]

I need a question to answer

7 0

3 years ago

Read 2 more answers

A giraffe can run up to 46.93 ft. per second. How far could a giraffe run in 1.8 seconds? Justify your answer

frozen [14]

84.474 because 46.93(1.8) = 84.474

3 0

3 years ago

Help please. Having some trouble with this question

xeze [42]

Answer:

The answer to your question is 55 ft

Step-by-step explanation:

Data

Person's height = 5 ft

Person's shadow = 10 ft

Tree's height = ?

Tree's shadow = 110 ft

- Use the Thales' theorem to solve this problem

Person's height / Person's shadow = Tree's height / Tree's shadow

- Substitution

5 / 10 = x / 110

-Solve for x

x = 5 (110) / 10

-Simplification

x = 550 / 10

-Result

x = 55 ft

-Conclusion

The tree is 55 ft height

5 0

3 years ago

IMAX theaters have the world’s largest screens. There are numerous IMAX theaters around the world. The Henry Ford Museum in Dear

SCORPION-xisa [38]

The dimensions would be 5 ft by 7 ft.

4 0

3 years ago

Read 2 more answers

given a geomatric progression 2,6,18,54... find the smallest value of n such that the nth term is greater than 100000​

given a geomatric progression 2,6,18,54... find the smallest value of n such that the nth term is greater than 100000