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RUDIKE [14]
3 years ago
11

A right rectangle prism has a length of 5 cm, a width of 4 cm, and a height of of 3 cm. The dimensions of the prism are doubled.

Mathematics
2 answers:
MaRussiya [10]3 years ago
6 0
As the volume of cuboid is given by,
l×b×h
as the dimensions are doubled,
l2×b2×h2
5×2×4×2×3×2
= 480 cm^3
vladimir2022 [97]3 years ago
5 0

Answer: 376 hope this helps!

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Choose the statement below that correctly compares the numbers 2.34 and 2.43.
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Answer:

the answer is 2.34<2.43

Step-by-step explanation:

it is because 2.34 is less than 2.43

< means less than

> means greater than

= means equal to

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I need help if you answer this I will give you 5 stars, a thank you and a brainiest
grigory [225]

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Step-by-step explanation:

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Find the length of the hypotenuse. Round your<br> answer to the nearest hundredth.
sergij07 [2.7K]

Answer:

8.06

Step-by-step explanation:

a^2 + b^2 = c^2

4^2 + 7^2 = c^2

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3 0
3 years ago
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

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3 years ago
Express as a trinomial.<br> (3x + 7)(3x + 4)
timama [110]

Answer:

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Step-by-step explanation:

(3x + 7)(3x + 4)\\= 3x(3x + 4) + 7(3x + 4)\\= 9x^2 + 12x + 21x + 28\\= 9x^2 + 33x + 28

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