Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
Answer:
infinetly many solutions
Step-by-step explanation:
Answer:
Pro: Monthly income to pay bills, buy food ,etc
Con: You many feel tied down, you could get abused at work (taken advantage of)
Answer:
hello your answer is 21 y=21
Step-by-step explanation:
3 times -7 is 21- hope i helped
Let the angle be x and it's complement be c.
Then, x = c + 88 and x + c = 90
Substitute the first equation in the second.
(c+88) + c = 90
2c+88 = 90
2c = 2
c =1
Compliment = 1
Angle = 89