Answer:
Step-by-step explanation:
No because there could simply be more older drivers on the road.
Answer:
Step-by-step explanation:
Answer:
![\displaystyle \sec A=\frac{65}{63}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csec%20A%3D%5Cfrac%7B65%7D%7B63%7D)
Step-by-step explanation:
We are given that:
![\displaystyle \csc A=\frac{65}{16}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Ccsc%20A%3D%5Cfrac%7B65%7D%7B16%7D)
Where <em>A</em> is in QI.
And we want to find sec(A).
Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:
![a=\sqrt{65^2-16^2}=\sqrt{3969}=63](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B65%5E2-16%5E2%7D%3D%5Csqrt%7B3969%7D%3D63)
So, with respect to <em>A</em>, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.
Since <em>A</em> is in QI, all of our trigonometric ratios will be positive.
Secant is the ratio of the hypotenuse to the adjacent. Hence:
![\displaystyle \sec A=\frac{65}{63}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csec%20A%3D%5Cfrac%7B65%7D%7B63%7D)
Answer:
4
Step-by-step explanation:
Hope this help
Answer:
w = 4 1/2
l = 6
Step-by-step explanation:
w = width
2w-3 = length
A = lw
27 = w(2w-3)
27 = 2w² - 3w
subtract 27 from each side:
2w² - 3w - 27 = 0
factor:
(2w-9)(w+3) = 0
solve each for 'w':
w = 9/2
w = -3 (This answer can be discounted because a length cannot be negative)
width = 9/2
length = 2(9/2) - 3 which is 6