Answer:
Set the area equal to x2, solve for x, and then multiply the value of x by 4.
Step-by-step explanation:
The area of the picture is given by
A = s^2 where s is the side length
Let the side length be x
A = x^2
Take the square root of each side
sqrt(A) = sqrt(x^2)
x = sqrt(A)
We want to find the perimeter since we are framing the border
P = 4s since the picture is a square
P = 4 * x
Answer: you go to lee high?
Step-by-step explanation:
Answer:
44
Step-by-step explanation:
1) we know that opposite sides of a parallelogram are congruent so
4x+28=10x+4
2) subtract 4 on both sides
4x+24=10x
3)subtract 4x on both sides
24=6x
4)divide by 6 on both sides
4=x
5)substitute for x
length of RS =10(4)+4
length of RD=44
Answer:
Distance problems are word problems that involve the distance an object will travel at a certain average rate for a given period of time.
The formula for distance problems is: distance = rate × time or d = r × t.
Things to watch out for:
Make sure that you change the units when necessary. For example, if the rate is given in miles per hour and the time is given in minutes then change the units appropriately.
It would be helpful to use a table to organize the information for distance problems. A table helps you to think about one number at a time instead being confused by the question.
Step-by-step explanation:
Respuesta: 12 estudiantes trajeron pilas
Solución:
Numero total de estudiantes: 30
Sea:
x: numero de estudiantes que trajeron pilas
y: numero de estudiantes que no trajeron pilas
x+y=30 (1)
La razón entre los estudiantes que trajeron pilas y los que no trajeron es como 2 es a 3:
Razón: r=x/y=2/3 (2)
Cuantos estudiantes trajeron pilas?
x=?
Tenemos un sistema de 2 ecuaciones con 2 incógnitas:
(1) x+y=30
(2) x/y=2/3
Vamos a resolver para x. Multiplicando en cruz en la segunda ecuación:
(2) 3x=2y
Depejando y: Dividiendo ambos lados de la ecuación entre 2:
3x/2=2y/2
3x/2=y
y=3x/2
Sustituyendo y por 3x/2 en la primera ecuación:
(1) x+y=30
x+3x/2=30
Sumando los términos en el lado izquierdo de la ecuación:
(2x+3x)/2=30
5x/2=30
Despejando x:
x=30*2/5
x=60/5
x=12
