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3 years ago

HELP PLEASE!!!

Mathematics

1 answer:

ch4aika [34]3 years ago

8 0

Answer:

The population of Bear in 2050 is 4750000

Step-by-step explanation:

A) The exponential growth equation for bear is as follows -

dN/dT = rmax * N

Where dN/dT = change in population

rmax is the maximum rate of change

N = Base population

B) Here the per capita rate of increase (r) will always be a positive value irrespective of the and hence we will assume this population to be growing exponentially.

C) dN/dT = rmax * N

D) dN / 5 = 2.5 * 380,000

dN = 5*2.5 * 380000

= 4750000

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Answer:

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Step-by-step explanation:

$273 ÷ 13 = $21

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3 years ago

Find value of x<br> A. 15<br> B. 18<br> C. 16<br> D. 19

tester [92]

Answer:

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Step-by-step explanation:

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3 years ago

Please help!! Thank you so much

stiv31 [10]

Answer:

I think answer is

b. (2,1)

:-)

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3 years ago

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Gnesinka [82]

Answer:

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3 years ago

Read 2 more answers

The daily high temperature on October 31 in a certain city is normally distributed with µ = 50 and σ = 8 . What is the probabili

tatyana61 [14]

Answer:

0.5328

Step-by-step explanation:

µ = 50

σ = 8

We are supposed to find the probability that the high temperature on October 31 in a randomly chosen year will be between 46 degrees and 58 degrees

$P(46 < x< 58)$

Formula : $Z=\frac{x-\mu}{\sigma}$

at x = 46

$Z=\frac{46-50}{8}$

$Z=-0.5$

Refer the z table for p value

p value = 0.3085

at x = 58

$Z=\frac{58-50}{8}$

$Z=1$

Refer the z table for p value

p value = 0.8413

$P(46 < x< 58)=P(x$

Hence the probability that the high temperature on October 31 in a randomly chosen year will be between 46 degrees and 58 degrees is 0.5328

8 0

3 years ago