14-9x=-8(10+x) slove and show check

A car has a gasoline

Delvig [45]

Answer:

Yes, look at the explanation:

Step-by-step explanation:

Calculate how many miles a car can drive with 1 gallon: 285 miles ÷ 10 = 28.5 miles with one gallon
Divide 500 by 28.5 to calculate how many gallons are needed: 500 ÷ 28.5 ≈ 17.543 - Therefore yes, it is possible because the car uses about 17.543 gallons of gasoline for 500 miles.

8 0

3 years ago

Draw a model to represent the problem 6/12 divided by 1/4

Sloan [31]

0.5/0.25?

Not really sure what ur asking

5 0

3 years ago

What are zeros of the function? What are there multiples? f(x) = 4x^3 -20x2 + 24x

bixtya [17]

When X=0, the function would be:

f(x) = 4x^3 -20x2 + 24x
0= 4x^3 -20x2 + 24x ----->divide all by x
x(4x^2 -20x + 24) =0 ------> split -20x into -12x and -8x
x(4x^2 -12x -8x + 24)
x{4x(x-3) - 8(x -3}
x(4x-8) (x-3)
x1= 0
x2= 8/4= 2
x3= 3

7 0

3 years ago

A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following

kiruha [24]

Answer:

After 47 days she will have more than 90 trillion pennies.

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

$1,2,4,8,16,32,.....$

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

$S_n=\dfrac{a(r^n-1)}{r-1}$

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

$\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}$

$\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}$

$\Rightarrow 90\times 10^{12}\le 2^n-1$

$\Rightarrow 2^n\ge 90\times 10^{12}+1$

$\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)$

$\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)$

$\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}$

$\Rightarrow n \ge 46.4$

$\Rightarrow n\approx 47$

8 0

3 years ago

Al oeste de Albuquerque, Nuevo México, la carretera 40 con rumbo al este es recta y tiene una fuerte pendiente hacia la ciudad.

alexgriva [62]

Usando el concepto de pendiente, se encuentra que el cambio en la distancia horizontal es de 10 pies.

La pendiente de una reta es la razón entre el cambio vertical y el cambio horizontal, o sea, cual el cambio vertical cuando el cambio horizontal es de 1.

En este problema, hay que:

La pendiente es -100, o sea, cuando hay un desplazamiento de un pie por adelante, hay una queda de 100 pies.
Bajado 1000 pies, entonces, aplicando la proporción:

1 pie H -> -100 pies V

x pie H -> -1000 pies V

Aplicando la multiplicación cruzada:

$-100x = -1000$