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lilavasa [31]
3 years ago
10

Anita and Brad are each riding on the same path. Anita began riding at start of the path and is riding at rate of 18 mile per ho

ur. Brad begin from a sport 10 mile ahead of her and I riding at rate of 13 mile per hour
Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

They will be at the same position after 2 hours.

Step-by-step explanation:

Here, it should be asked the time it will take for Anita to catch Brad.

Anita began riding at start of the path and is riding at rate of 18 mile per hour.

This means that, after t hours, her position will be given by:

A(t) = 18t

Brad begin from a sport 10 mile ahead of her and I riding at rate of 13 mile per hour

This means that, after t hours, his position will be given by:

B(t) = 10 + 13t

After how much time will they be at the same position?

This is t for which:

A(t) = B(t)

So

18t = 10 + 13t

5t = 10

t = \frac{10}{5}

t = 2

They will be at the same position after 2 hours.

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lisov135 [29]

Answer:

8

Step-by-step explanation:

If a = -16 and b = -2, just substitute the values in for the equation.

a/b = -16/-2

The negatives cancel out, since both the numerator <em>and</em>  denominator are <em>both</em>  negative.

-16/-2 = 16/2

If you symplify, you get 8.

So, your answer is 8

4 0
3 years ago
Which data will most likely show a negative correlation when graphed on a scatter plot?
Elis [28]

Answer:

Outside Temperature and Cost of Heating Bill

Step-by-step explanation:

The temperature could possibly go down and if its cost it will definitely go  down.

8 0
4 years ago
Read 2 more answers
I got 2 questions.
alexandr402 [8]

Answer:

1. In triangle ABC,

AC = a = 10, BC =b= 7 and ∠ C = 90°

By cosine law,

AB^2 = 7^2 + 10^2 - 2\times 7\times 10 cos 90^{\circ}

AB^2 = 49 + 100 - 0

AB^2 = 149

AB= \sqrt{149}

Now, by the law of sine,

\frac{sin B}{10} = \frac{sin90^{\circ}}{\sqrt{149} }

sin B = \frac{10}{\sqrt{149} }

\angle B = 55.0079798014\approx 55.008^{\circ}

2. In triangle ABC,

∠B = 30°,  AB=c=10 and ∠C = 90°

∠A = 180°-(30+90)°=60°

\frac{AC}{10}=sin30^{\circ}

⇒ AC = \frac{10}{2} = 5

By Pythagoras,

CB^2 = AB^2 - AC^2=10^2 - 5^2 = 100 - 25 = 75

⇒ CB = \sqrt{75} =8.66025403784\approx 8.66



6 0
3 years ago
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NC0 + nC3 + nC6 + nC9 + ...<br><br> what does this equal to?
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5 0
4 years ago
A car was sold 24 standard washed in a day , which was 25% of their total sales for that day . What was the total amount of wash
-Dominant- [34]

Answer:

96

Step-by-step explanation:

GIVEN: A car was sold 24 standard washed in a day , which was 25\% of their total sales for that day.

TO FIND: Total amount of washes that the car wash sold that day.

SOLUTION:

Let the total sales of car washes sold for that day =x

total number of standard car washes sold s=24

As, total standard car washes sold are 25\% of total sales in a day

s=\frac{25}{100}x

putting value in equation

24=\frac{25}{100}x

x=\frac{24}{25}\times100

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Hence the total  number of car washes sold that day are 96

4 0
4 years ago
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