Data for the question :
102.05 99.85 112.3 97.15 111.23 105.37 105.64 106.5 102.97 107.82 106.36 111.24 107.28 114.14 106.28 106.96 98.25 111.55 107.75 101.02 101.12 97.7 97.66 100.54 115.77 112.91 111.04 112.15 102.87 101.14 107.13 108.56 109.56 103.57 108.68 104.59 116.74 116.22 100.22 103.97 111.2 109.34 115.78 101.59 107.93 104.23 96.25 103.84 102.47 102.96 99.26 101.42 108.58 107.69 99.88 102.71 111.25 99.4 117.04 106.35 110.44 102.34 107.25 107.63 105.2 109.14 115.54 101.51 108.49 112.32 109.27 97.54 102.46 105.94 109.42 111.05 102.63 106.99 102.03 108.84 118.8 108.64 95.35 105.47 104.45 102.15 111.4 108.27 104.82 108.4 109.05 116.11 103.7 121.2 99.62 102.81 109.56 103.35 113.02 103.79
Answer:
Range = 25.35
Variance = 29.46
Standard deviation = 5.43
The variation in price of Prozac is high
Step-by-step explanation:
The range of the data :
Maximum - Minimum.
121.2 - 95.35 = 25.35
The variance, s :
s² = Σ(X - m²) / n - 1
Mean, m = Σx / n
X = individual data point
m = mean of data
n = sample size
Using a calculator of save time and ensure accuracy :
s² = 29.45522
The standard deviation, s
s = sqrt(variance)
s = sqrt(s²)
s = sqrt(29.45522)
s = 5.42726.
The range, variance and standard deviation, all measure the degree of variation in a dataset. The values of these statistical measure obtain for the price of 1 product across different pharmaceutical stores, suggests thatvthe variation in price is high;
With a range of about 25.35 and standard deviation of 5.43
Answer:
A
Step-by-step explanation:
Answer:
A, B
Step-by-step explanation:
Solve by factoring.
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
Answer:
Option D is correct
Step-by-step explanation:
Statement 1
Average weight of 3 dogs = 55 pounds
Total weight of 3 dogs = 55 × 3
Total weight of 3 dogs = 165 pound
Statement 2
Average weight of 5 cats = 9 pounds
Total weight of 5 cats = 9 × 5
Total weight of 5 cats = 45 pounds
New Average = 165 + 45/8
New Average = 210/8
New Average = 26.25 pounds
