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WARRIOR [948]
3 years ago
15

?/1 If a test is worth 45 points, how many points would a student need to earn to get a score of 90%?

Mathematics
1 answer:
notka56 [123]3 years ago
8 0

Answer:

40.5 points

Step-by-step explanation:

To start off, I would set up a proportion. You're trying to find how many points out of the total 45 would give you a 90%.

90% as a fraction would be \frac{90}{100}.

When you set the two equal to one another, you get this:

\frac{x}{45} = \frac{90}{100}

The bottom numbers are the total amount of points, and the top is how many points a student got.

To solve for x, which is the number of points a student would need to earn, you can cross multiply.

After you do that, you should get:

100x = 4050

To isolate x, you can divide by 100 on both sides.

x = \frac{4050}{100} = 40.5 points

To check your answer, all you have to do is divide.

40.5 ÷ 45 = 0.9

0.9 as a percent is 90%.

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If measure KL=136 and measure LH= 113. find measure angle KJH
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D) 111

Step-by-step explanation:

In order to find ∠KJH we must find the measure of arc KH

Note that ∠KJH is a central angle and arc KH is the arc it intercepts

Because ∠KJH is a central angle it equal the measure of its intercepted arc

Thus, ∠KJH = arc KH

J is a circle that is made up of 3 arc; KL, LH and KH

If you didn't know the sum of the arcs in a circle = 360°

Which means that arc KL + arc LH + arc KH = 360

If arc KL = 136 and arc LH = 113

Then 136 + 113 + arc KH = 360

                        ^ ( note that we just created an equation that we can use to

                            solve for arc KH )

We now solve for arc KH

136 + 113 + arc KH = 360

* combine like terms *

136 + 113 = 249

we now have 249 + arc KH = 360

* subtract 249 from each side *

249 - 249 cancels out

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We're left with arc KH = 111°

Like stated previously arc KH = ∠KJH

Hence, ∠KJH = 111°

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