20 (units)
Distance formula is:
Sqrt of (x-x1)^2+(y-y1)^2
So define which coordinate is (x,y) and what (x1,y1)
I’m going to define (-10,-7) as (x,y) and (2,9) as (x1,y1)
So plug in your variables!
Sqrt(-10-2)^2+(-7-9)^2
Sqrt-12^2+-16^2
Sqrt144+256
Sqrt400
So sqrt of 400 is 20! :))
1. This is a very easy question as you can just plug in 2 x-values and get the y-value, run a line through it, and you are done.
For example,
x = 2t
x = 2(2) = 4
x = 2(3) = 6
Now, you know there are points at (2, 4) and (3, 6).
2. This one is a little tricky, but all it's saying is that it has a specified domain. The parametric equation only works for values -2 ≤ t ≤ 3. So, you can do the exact same thing, except your line will only exist for points through the x-values -2 and 3. Let's plug in numbers:
y = t + 5
y = -2 + 5 = 3
y = 1 + 5 = 6
Now you know that this line runs through (-2, 3) and (1, 6). Remember, your line starts at -2 and ends at 3. It can't go any further than that.
Answer: Ok
Step-by-step explanation:
(x + 2) = 3
-2 -2
0 1
x = 1
Answer:
15
Step-by-step explanation:
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