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2 years ago

Y-x=2x-2/3y Written in y=mx+b form

Mathematics

1 answer:

FromTheMoon [43]2 years ago

8 0

1 2/3y = 3x
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Find the area of this figure.

ryzh [129]

Answer:

1824 square inches

Step-by-step explanation:

First, separate the figure into two sections. The triangle on top, and the rectangle on the bottom.

to get the area of the triangle, simply multiply height times width and divide by two.

48 x 12 = 576

576/2 = 288

the area of the triangle is 288 sq in

next, multiply the height and width of the rectangle to get its area.

32 x 48 = 1536

add 1536 to 288 to get the area of the complete figure

1536 + 288 = 1824

the answer is 1824 square inches

7 0

2 years ago

Please answer this correctly

zysi [14]

Answer:

it's 2.31 mins

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2 years ago

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What is the slope of the line that passes through the points (-6,-4) and

AveGali [126]

Answer:

Step-by-step explanation:

Use slope intercept form: $\frac{y_2-y_1}{x_2-x_1}$

$\frac{-4-(-4)}{-12-(-6)}$ = $\frac{0}{-6}$ = 0

5 0

2 years ago

Write an algebraic equation or expression or the word phrase<br><br> 25y=5

lidiya [134]

25 times a letter Y = a number 5

5 0

3 years ago

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HELPPPPP ASAPPPP

KATRIN_1 [288]

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :

$h(t)=-16t^2+20t+6$ ....(1)

The volleyball reaches its maximum height after 0.625 seconds.

For maximum height,

Put $\dfrac{dh}{dt}=0$

Now put t = 0.625 in equation (1)

$h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}$

So, the maximum height of the volleyball is 12.25 feet.

5 0

3 years ago