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mars1129 [50]
3 years ago
10

Can you tell me the answers 3-8

Mathematics
1 answer:
Andrei [34K]3 years ago
4 0
3)5 4/6 4) 13 8/10 5) 11 5/12 6) 11 10/24 7) 5 8/16 8) 15 8/20

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lisabon 2012 [21]

Answer: the page wont load all the way

Step-by-step explanation: she gonna need a lot of paint tho

7 0
3 years ago
Write the slope-intercept form of the equation of each line given the slope and y-intercept
amid [387]
The slope-intercept form of the equation for a line is ...
  y = (Slope)x + (y-intercept)

Put the given information in the appropriate spot in the equation. Simplify as required.
  y = (-1/3)x + 0
can be simplified to

y = (-1/3)x
6 0
3 years ago
Find the horizontal asymptote
eimsori [14]

Answer:

Correct answer:  h = 3/5  or y = 3/5

Step-by-step explanation:

Given:

h(x) = (3x² - 9x - 4) / (5x² - 4x + 8)

h = lim x -> ∞ (3x² - 9x - 4) / (5x² - 4x + 8) the numerator and denominator will be divided by x² and get

h = lim x -> ∞ (3 - 9(1/x) - 4 (1/x²)) / (5 - 4(1/x) + 8 (1/x²)

The terms 1/x and 1/x²  when x strives ∞ they strives 0

x -> ∞ ⇒ 1/x -> 0  and x -> ∞ ⇒ 1/x² -> 0

h = (3 - 0 - 0) / (5 - 0 + 0)

Horizontal asymptote is h = 3/5 or y = 3/5

God is with you!!!

5 0
3 years ago
HELP HELP !! & PlEASE SHOW WORK ! What would be the compound interest rate if Tom borrowed $6,000 at a 3% interest rate for
In-s [12.5K]

Answer:

Compound interest = $365.4

Step-by-step explanation:

Given:

Amount borrowed = $6,000

Rate of interest = 3%

Number of year =  year

Find:

Compound interest

Computation:

A = P[1+r]ⁿ

Amount after 2 year = 6,000[1 + 3%]²

Amount after 2 year = 6,000[1 + 0.03]²

Amount after 2 year = 6,000[1.03]²

Amount after 2 year = 6,000[1.0609]

Amount after 2 year = 6,365.4

Compound interest = Amount after 2 year - Amount borrowed

Compound interest = 6,365.4 - 6,000

Compound interest = $365.4

3 0
2 years ago
Someone please help me I’ll give out brainliest please dont answer if you don’t know
lisabon 2012 [21]

Answer:

If you are looking for x your answer will be x=2

5 0
3 years ago
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