All categories

3 years ago

Can you tell me the answers 3-8

Mathematics

1 answer:

Andrei [34K]3 years ago

4 0

3)5 4/6 4) 13 8/10 5) 11 5/12 6) 11 10/24 7) 5 8/16 8) 15 8/20

You might be interested in

There were 436 tickets purchased for a major league baseball game. The general admission tickets cost $6.50 and the upper reser

Nataly [62]

Answer:

How many general admission tickets were purchased? __136__

How many upper reserved tickets we purchased? _300_

Step-by-step explanation:

Let the number of general tickets = g.

Let the number of reserved tickets = r.

6.5g + 8r = 3284

g + r = 436

6.5g + 8r = 3284

(+) -8g + -8r = -3488

--------------------------------

-1.5g = -204

g = 136

g + r = 436

136 + r = 436

r = 300

Answer:

How many general admission tickets were purchased? __136__

How many upper reserved tickets we purchased? _300_

8 0

2 years ago

Read 2 more answers

This is already late but please help

Nostrana [21]

Answer: 12.5

Step-by-step explanation:

x/10 = 10/8

reduce the fraction with 2

x/10=5/4

simplify the equation using cross-multiplication

4x=50

divide both sides by 4

x=25/2

x=12.5

3 0

2 years ago

12,348 <img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula">

Diano4ka-milaya [45]

Answer:

radius of the sphere (r) = 21 units

Step-by-step explanation:

here's the solution : -

=》

$12348\pi = \frac{4}{3} \times \pi \times {r}^{3}$

=》

${r}^{3} = 12348 \times \frac{3}{4}$

( pi cancel out )

=》

${r}^{3} = 9261$

=》

$r = 21$

4 0

2 years ago

Which of the points shown below are on the line given by the equation y = 2x? Check all that apply.

aleksklad [387]

Hey there I just saw no one answered this problem and I know this is a little late but I will answer it anyways.

Answer: The answer to this problem would be points A and B

3 0

2 years ago

Please round to the nearest tenth if possible.

Butoxors [25]

$\bf \cfrac{64~\underline{mi}}{\underline{hr}}\cdot \cfrac{\underline{hr}}{60~sec}\cdot \cfrac{5200~ft}{\underline{mi}}\implies \cfrac{64\cdot 5200~ft}{60~sec}\implies \cfrac{16640~ft}{3~sec}
\\\\\\
\approx 5546.67\frac{ft}{sec}\\\\
-------------------------------\\\\
\cfrac{6000~\underline{lbs}}{\underline{day}}\cdot \cfrac{ton}{2000~\underline{lbs}}\cdot \cfrac{7~\underline{day}}{week}\implies \cfrac{6000\cdot 7~ton}{2000~week}\implies 21.00\frac{ton}{week}$

$\bf -------------------------------\\\\
\cfrac{2~\underline{lbs}}{\underline{week}}\cdot \cfrac{16~oz}{\underline{lbs}}\cdot \cfrac{\underline{week}}{7~day}\implies \cfrac{2\cdot 16~oz}{7~day}\implies \cfrac{32~oz}{7~day}\approx 4.57\frac{oz}{day}$

8 0

3 years ago