The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
2x-6=90 would be the answer
Answer:
subtracting 5 from both sides
Step-by-step explanation:
please mark brainliest lol :)
Part A: it is linear because it is not curving and it consists of straight lines.
Part B: in side A it is increasing because it has a positive slope. In side b it is constant because the slope is 0 since it is straight. Finally, side C is decreasing because the slope is negative.
Part C: during side A the ant is crawling out of the hole in 2 seconds. After that, the ant stops for 2 more seconds as shown in side B. Then, he crawls back into the hole as shown by the decrease in distance due to the slope.
Hope this helps!!!
Ok so this question:
y + 1 = - ( x - 2 ) (distribute the negative inside the parenthesis)
y + 1 = -x + 2 (substitute the y= -1)
-1 + 1 = -x + 2
0 = -x + 2 (take two to the other side)
-2 = -x (divide the negative away from x)
2 = x
