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Likurg_2 [28]
2 years ago
5

Find the area. HELP PLEASE!!!!!!​

Mathematics
2 answers:
Andreyy892 years ago
8 0

Answer:

Step-by-step explanation:

Givens

h = 14

b1 = 34

b2  = 45

Formula

A = (b1 + b2)*h /2                   Substitute into the formula

Solution

A = (34 + 45)*14/2                 Combine the brackets

A = (79) * 14/2                       Do the division

A = 79 * 7

Area = 553  cm^2

kaheart [24]2 years ago
3 0

Answer:

616

Step-by-step explanation:

The equation to find the area of a trapezoid is:  A = ½ (b^1+b²) h.

b1=43

b2=45

h=14

Plug the variables in and solve.

A=\frac{1}{2} (43+45)14

A=\frac{1}{2} (88)14

A=\frac{1}{2} (1232)

A=616

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daw

Step-by-step explanation:

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3 years ago
Which will result in a difference of squares?
oksian1 [2.3K]

Answer:

C

Step-by-step explanation:

The correct answer is C, love from Gauthmath

3 0
2 years ago
If a = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft, what is the area of the living room and hallway together?
Anvisha [2.4K]

Answer:

The area of the living room and hallway together = 437ft²

Question:

The complete question related to the one above found at 'Geometry in class' is stated below:

Abbey is getting new carpet in her living room and hallway.

The following diagram shows the two together.

If = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft, what is the area of the living room and hallway together?

Find attached the diagram of the question.

Step-by-step explanation:

To determine the area of the living room and hallway together, we would break the diagram into two rectangles.

Calculate the area of each and sum the two outcomes together.

Find attached the diagrams of the solution.

Given: a = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft,

Area of rectangle = length × breadth

Area of rectangle 1 = a × (d-b)

= 38 × (19-15) = 38× 4

Area of rectangle 1 = 152ft²

Area of rectangle 2 = c × b

= 19 × 15 = 285

Area of rectangle 2 = 285ft²

The area of the living room and hallway together = Area of rectangle 1 + Area of rectangle 2

= 152ft² + 285ft²

The area of the living room and hallway together = 437ft²

5 0
3 years ago
the high temperature one day was -1°f. The low temperature was-5°f. What was the difference between the high and low temperature
Kazeer [188]

The answer is 4.

Hope this helps you!

3 0
3 years ago
Find the Quadratice function <img src="https://tex.z-dn.net/?f=y%3Da%28x-h%29x%5E%7B2%7D" id="TexFormula1" title="y=a(x-h)x^{2}"
Pani-rosa [81]

Given:

Consider the quadratic function is

y=a(x-h)^2+k

With given vertex (5,8) and given point (1,3).

To find:

The equation of quadratic function.

Solution:

The quadratic function is

y=a(x-h)^2+k               ...(i)

Where, (h,k) is the vertex and a is a constant.

Vertex is (5,8). So,

(5,8)=(h,k)

h=5,k=8

Putting h=5,k=8 in (i), we get

y=a(x-5)^2+8           ...(ii)

The given point is (1,3). Putting x=1 and y=3 in  (ii), we get

3=a(1-5)^2+8

3-8=a(-4)^2

-5=16a

-\dfrac{5}{16}=a

Putting a=-\dfrac{5}{16} in (ii), we get

y=-\dfrac{5}{16}(x-5)^2+8

Therefore, the required quadratic function is y=-\dfrac{5}{16}(x-5)^2+8.

4 0
3 years ago
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