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3 years ago

How to find the inverse of each function for example like this one: h(x)=5/4x

2 answers:

4 0

First rewrite it like this
1. y=5/4x
Then, make X the subject
2.4x=5/y
x=(5/y)÷4
3. Once done, simply replace x with h(x)^-1 and y with x
h(x)^-1= (5/x)÷4
Sorry I'm not very good at rearranging formula but hope this helps :)

kolbaska11 [484]3 years ago

4 0

1. y=5/4x
Then, make X the subject
2.4x=5/y
x=(5/y)÷4
3. Once done, simply replace x with h(x)^-1 and y with x
h(x)^-1= (5/x)÷4

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7/10, 3/20, 22/25, 2/5 in order from least to greatest

swat32

3/20, 2/5, 7/10 & 22/25

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3 years ago

The quotient of m2 – 9 divided by m-3 is<br> a) m-3 b) m+3 c) m

DaniilM [7]

Answer:m+3

Step-by-step explanation:

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2 years ago

I need help! Will this would be very appreciated!pls

elena-s [515]

Answer:

No real

solution

Step-by-step explanation:

Firstly, let us check if we would be having a real solution

We start by rewriting the equation

We have this as;

8x^2 -25x + 24 = 0

We proceed to get the discriminant

Mathematically, we have this as;

D = b^2 - 4ac

b is the coefficient of x which is -25

a is the coefficient of x^2 which is 8

c is the last number which is 24

So we have;

D = (-25)^2 - 4(8)(24)

D = 625 - 768 = -143

Since the value of the discriminant is negative, there cannot be real roots

What we have as solution are complex roots

6 0

2 years ago

Use the identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx) to determine the value of the sum of three integers given: the sum of

fenix001 [56]

ffn

$x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)$

$x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))$

the sum of their squares is 110, So $x^2+y^2 + z^2= 110$

the sum of their cubes is 684, so $x^3+y^3 + z^3= 684$

the product of the three integers is 210, so xyz= 210

the sum of any two products (xy+yz+zx) is 107

Now we plug in all the values in the identity

$x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))$

684 - 3(210) = (x+y+z)(110-107)

684 - 630 = (x+y+z)(3)

54 = 3(x+y+z)

Divide by 3 on both sides

18 = x+y+z

the value of the sum of three integers is 18

3 0

3 years ago