A body oscillates with simple harmonic motion along the x-axis. its displacement varies with time according to the equation x(t)
= a sin(ω t + φ). if a = 5 m, ω = 3.444 rad/s, and φ = 1.0472 rad, what is the acceleration of the body at t = 3 s? note: the argument of the sine function is in radians rather than degrees. answer in units of m/s 2 .
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Given:
Length = 3x + 6y cm
Area = 3x² + 9xy + 6y²
Because Area = Width * Length, therefore
Width = Area/Length
= (3x² + 9xy + 6y²)/(3x + 6y).
Width =
Answer: x+y
Length = 3x + 6y cm
Area = 3x² + 9xy + 6y²
Because Area = Width * Length, therefore
Width = Area/Length
= (3x² + 9xy + 6y²)/(3x + 6y).
Width =
Answer: x+y