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babunello [35]
3 years ago
8

What type of angle is r

Mathematics
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

radius i think

Step-by-step explanation:

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Find the missing angles using either the triangle sum theorem (a2+b2=c2) or inverse trigonometric ratios
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using trigonometry:-

cos of angle ? = 7/16

so ? = arccos 7/16 = 64.06 degrees


The other angle is 90 - 64.06 = 25.94 degrees

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w=\dfrac{1}{2}l-4
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If N/8+6=58, then N equals?
GaryK [48]
N equals <em>416</em>

Hope this helps!

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Follow the steps below to find the mean for the set of data. Use the work shown to help you. Data set: 6, 5, 8, 5, 9, 6, 7, 5, 1
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7

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3 years ago
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The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)

\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

6 0
3 years ago
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