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meriva
3 years ago
9

Explain how muscles are effected by space travel

Physics
1 answer:
sleet_krkn [62]3 years ago
3 0
Hopes this helps:

Answer: Because astronauts work in a weightless environment, very little muscle contraction is needed to support their bodies or move around.
Without regular use and exercise our muscles weaken and deteriorate. It’s a process called atrophy.

Have a great day.
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If a 500kg elephant is sliding across a frictionless patch of ice, how much force is needed to keep the elephant from slowing do
Varvara68 [4.7K]

Answer:

<h3>4905N</h3>

Explanation:

The force needed to keep the elephant from slowing down is expressed as shown according to Newtons second law of motion.

Force = mass * acceleration due to gravity

Given

Mass of elephant = 500kg

acceleration due to gravity = 9.81m/s²

Force = 500*9.81

Force = 4905N

<em>Hence the force needed to keep the elephant from slowing down is 4905N</em>

5 0
3 years ago
Which of the following best compares longitudinal waves with transverse waves?
Semmy [17]
In longitudinal waves, the particles of the medium or a system displaces back and forth(parallel) in the direction of the propagation of waves. In transverse waves, the particles of the medium or a system displaces perpendicular to the direction of the propagation of waves. Therefore, C is correct. 
5 0
3 years ago
Read 2 more answers
Which of the options below has the correct number of each element for the compound?
slamgirl [31]

Answer:

there are no options buddy

7 0
3 years ago
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What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble?
DiKsa [7]

Answer:

So visible wavelength which is possible here is

416 nm and 693.3 nm

Explanation:

As we know that for normal incidence of light the path difference of the reflected ray is given as

2\mu t + \frac{\lambda}{2} = \Delta x

so here we can say that for maximum intensity condition we will have

\Delta x = N\lambda

so we have

2\mu t + \frac{\lambda}{2} = N\lambda

now for visible wavelength we have

for N = 1

2\mu t = \frac{\lambda}{2}

\lambda = 4\mu t

\lambda = 4(\frac{4}{3})(390 nm)

\lambda = 2080 nm

for N = 2

\lambda = \frac{4\mu t}{3}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{3}

\lambda = 693.3 nm

for N = 3

\lambda = \frac{4\mu t}{5}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{5}

\lambda = 416 nm

6 0
4 years ago
Need some help with homework but where doing it in class rn
Brilliant_brown [7]

Answer:

now it lets me. B

Explanation:

hope that helps

6 0
3 years ago
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