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tino4ka555 [31]
3 years ago
7

Croquet balls must have a mass of 0.50 kg. A red croquet ball is moving at 5 m/s. It strikes an at-rest green croquet ball head-

on and then continues to move in the same direction, but with a speed of 2 m/s. What is the final speed of the green ball?
A.
5 m/s

B.
0.5 m/s

C.
2 m/s

D.
3 m/s
Physics
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

Explanation:

The Law of Momentum Conservation for us has the equation

[m_rv_r+m_gv_g]_b=[m_rv_r+m_gv_g]_a and filling in:

[(.50)(5.0)+(.50)(0)]=[(.50)(2.0)+(.50)v_g] and

2.5 = 1.0 + .50v and

1.5 = .50v so

v = 3 m/s

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Yolanda might put more items to the desk to make it heavier, requiring more force.

We need to learn more about the force acting on an object in order to locate the solution.

<h3>How can the force that is required to modify the motion be increased?</h3>
  • We are aware that the word for force is,

                            F=ma

where m denotes the object's mass and an its acceleration

  • There are two ways to increase the force required to alter the motion of the table.
  • One is to increase the mass, and the other is to accelerate it more quickly.
  • Otherwise, there will be a lot of friction between the surfaces, making it difficult to move without exerting a lot of force.

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Which is at rest relative to a seated passenger in a moving car?
AnnyKZ [126]
THAT'S EASY BRO! the answer is the Seat!
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The correct answer to this problem is C
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State whether a speedometer reading of 45 km/h is the average or instantaneous speed of the car
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Consider the flow of an incompressible Newtonian fluid between two parallel plates that are 4 mm apart. If the upper plate moves
marin [14]

Answer:

Net flow rate = 0.00035 m³/s

Explanation:

The speed of plate 1, U₁ = 5 m/s

The speed of plate 2, U₂ = 1.5 m/s

The two plates are moving in different directions, the net speed will be gotten by taking the difference of the average of the two plates

The average speed due to the movement of plate 1 = U₁/2 = 5/2 = 2.5 m/s

The average speed due to the movement of plate 2 = U₂/2 = 1.5/2

      = 0.75 m/s

The net average speed of the fluid= U₁/2 - U₂/2

The net average speed of the fluid = 2.5 - 0.75 = 1.75 m/s

Net flow rate = Net average speed * Area of the plate

Width of the plate, v = 5 cm = 0.05 m

Distance between the plates = 4 mm = 0.004 m

Area = 0.05 * 0.004

Area = 0.0002 m²

Net flow rate = 1.75 * 0.0002

Net flow rate = 0.00035 m³/s

8 0
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