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tino4ka555 [31]
3 years ago
7

Croquet balls must have a mass of 0.50 kg. A red croquet ball is moving at 5 m/s. It strikes an at-rest green croquet ball head-

on and then continues to move in the same direction, but with a speed of 2 m/s. What is the final speed of the green ball?
A.
5 m/s

B.
0.5 m/s

C.
2 m/s

D.
3 m/s
Physics
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

Explanation:

The Law of Momentum Conservation for us has the equation

[m_rv_r+m_gv_g]_b=[m_rv_r+m_gv_g]_a and filling in:

[(.50)(5.0)+(.50)(0)]=[(.50)(2.0)+(.50)v_g] and

2.5 = 1.0 + .50v and

1.5 = .50v so

v = 3 m/s

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3 0
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An unwary football player collides with a padded goalpost while running at a velocity of 9.50 m/s and comes to a full stop after
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Answer:

(a) The collision lasts for 0.053 s.

(b) The deceleration is 180.5 m/s².

Explanation:

Given:

Initial velocity of the player (u) = 9.50 m/s

Final velocity of the player (v) = 0 m/s (Comes to a stop)

Displacement of the player (S) = 0.250 m

We know that, using equation of motion relating displacement (S), acceleration (a), initial velocity (u) and final velocity (v), we have:

v^2=u^2+2aS

Expressing in terms of 'a', we get:

a=\frac{v^2-u^2}{2S}

Plug in the given values and solve for 'a'. This gives,

a=\frac{0-9.50^2}{2\times 0.250}\\\\a=\frac{-90.25}{0.5}=-180.5\ m/s^2

Therefore, the acceleration of the player is -180.5 m/s². So, the deceleration is 180.5 m/s².

Now, using the first equation of motion, we have:

v=u+at\\\\t=\frac{v-u}{a}

Plug in the given values and solve for 't'. This gives,

t=\frac{0-9.5}{-180.5}\\\\t=0.053\ s

Therefore, the the collision will last for 0.053 s.

(a) The collision lasts for 0.053 s.

(b) The deceleration is 180.5 m/s².

8 0
3 years ago
Based on the information in the table, which mineral is LEAST likely to be found in Earths rocks
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Answer:

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A truck traveled 400 meters north in 80 seconds and then it traveled 300 meters east in 70 seconds. The magnitude of the average
Varvara68 [4.7K]

Answer:

3.3m/s

Explanation:

You first get the total time (80 + 70 = 150s).

Then you would find the displacement of the truck. To do that you would do component method (vector addition), so since its a right triangle (North and East), displacement is 400^2 + 300^2 = d^2.

d= 500m.

So now that you have displacement and time, you can find the velocity:

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