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Natalka [10]
3 years ago
7

A butcher is mixing ground turkey breast that is 98% lean and beef that is 90% lean to make a blend that is 92.4% lean. Determin

e how many pounds of turkey and beef are needed if she wants 100 pounds of the blend.
Follow the steps below:

1. Identify what x and y represent.
2. Write an equation to relate x and y.
3. Write a 2nd equation relating x and y.
4. use either elimination or substitution to solve for x and y.

Could someone also add an explanation on how they solve the problem? These problems always give me a hard time.
Mathematics
1 answer:
Paul [167]3 years ago
7 0
See brainly.com/question/8613376 for one way to work mixture problems.

The proportion of beef will be
.. (98 -92.4)/(98 -90) = 5.6/8 = 0.7

70 pounds of beef and 30 pounds of turkey are needed.

_____
1. I would prefer to use "t" and "b" as variables, rather than x and y. That way I can more easilly keep straight that they represent pounds of turkey and pounds of beef, respectively.

2. t + b = 100 . . . . . we want 100 pounds of mix

3. 98%*t +90%*b = 92.4%*100 . . . . . total pounds of lean meat

4. Using subsitution for t, we have
.. 98%*(100 -b) +90%*b = 92.4%*100
.. b*(98 -90) -98*100 = -92.4*100 . . . . . . multiply by -100, collect b terms
.. b = (98 -92.4)*100/(98 -90) . . . . . . . . . add 98*100 and divide by b coefficient
note that this expression is exactly the one we used to write down the answer above.
.. b = 5.6*100/8 = 70 . . . . . . . y, if you like
.. t = 100 -b = 30 . . . . . . . . . . x, if you like

70 pounds of beef and 30 pounds of turkey are needed.
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STANDARD DEVIATION
givi [52]

Answer:

0.1527

Step-by-step explanation:

Standard Deviation = √p × q/n

Reynolds: 63%

Bachmann: 37%

n = 100

Standard Deviation = √0.63 × 0.37/100

= √(0.02331)

= 0.1526761278

≈ 0.1527

4 0
3 years ago
The Cunninghams are moving across the country. Mr. Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 40mph and sh
svp [43]
Recall your d = rt, distance = rate * time

now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.

However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Mr Cunningham}&d&40&t\\
\textit{Mrs Cunningham}&d&80&t-3
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=40t\\
d=80(t-3)\\
----------\\
\boxed{40t}=80(t-3)
\end{cases}
\\\\\\
\cfrac{40t}{80}=t-3\implies \cfrac{t}{2}=t-3\implies t=2t-6\implies 6=2t-t
\\\\\\
6=t
5 0
3 years ago
Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
Please help I really do not understand its turned in today. I WILL GIVE BRAINLIEST :)
8090 [49]

Answer:

Total area of new carpeting installed: 368

Step-by-step explanation:

What I did is too complicated to write down, so I'll just show you the math:

(12 * 8) * 2 (The area of the bedrooms)

11 * 16 (The area of the livingroom)

6 0
2 years ago
Which statement below best describes the transformation of parallelogram WXYZ to parallelogram W' X' Y' Z'?
Arisa [49]
The answer is B. A reflection across the x-axis.
6 0
3 years ago
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