Answer:
O-2(x+5)
Step-by-step explanation:
I have to much time on my hands
Answer:
(a) 0.2061
(b) 0.2514
(c) 0
Step-by-step explanation:
Let <em>X</em> denote the heights of women in the USA.
It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.
(a)
Compute the probability that the sample mean is greater than 63 inches as follows:

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.
(b)
Compute the probability that a randomly selected woman is taller than 66 inches as follows:

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.
(c)
Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.
Answer:
1/2
Step-by-step explanation:
4/8 are red. If you simplify that you get 1/2.
Answer:

Step-by-step explanation:
S = (x1,y1) = (0,-5)
T = (x2,y2) = (-8,-7)
<u>Using distance formula to find the length of ST</u>.
![|ST|= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\|ST| = \sqrt{(-8-0)^2+(-7-(-5))^2} \\\\|ST| = \sqrt{(-8)^2+(-7+5)^2} \\\\|ST| = \sqrt{64+(2)^2}\\\\|ST| = \sqrt{64+4} \\\\|ST| = \sqrt{68} \\\\|ST| = 8.2 \ units\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%7CST%7C%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B%28-8-0%29%5E2%2B%28-7-%28-5%29%29%5E2%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B%28-8%29%5E2%2B%28-7%2B5%29%5E2%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B64%2B%282%29%5E2%7D%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B64%2B4%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B68%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%208.2%20%5C%20units%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
23
Step-by-step explanation: