So to work this out we need to find the 4th root of each of those and pick the one that gives an integer.
A:
![\sqrt[4]{1.6*10^1^1} = 632.455...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E1%7D%20%3D%20632.455...)
This is a decimal therefore <em>not</em> an integer.
B:
![\sqrt[4]{1.6*10^1^2} =1124.682...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E2%7D%20%3D1124.682...)
Again a decimal, therefore <em>not </em>an integer.
C:
![\sqrt[4]{1.6*10^1^3} =2000](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E3%7D%20%3D2000)
This is a whole number, so it <em>is </em>an integer.
D:
![\sqrt[4]{1.6*10^1^4} =3556.558...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E4%7D%20%3D3556.558...)
Decimal, therefore <em>not </em>an integer
E:
![\sqrt[4]{1.6*10^1^5} =6324.555...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E5%7D%20%3D6324.555...)
Again a decimal, <em>not</em> an integer.
The only one that gives an integer when put to the 4th root is C, therefore:
could be A^4, as the 4th root of it is an integer.
H (4.84) will be the correct answer
Answer:y=-4
Step-by-step explanation:
Multiply -4 by -2 you get positive 8 rewrite the equation subtract 8 from both sides that leaves you with 8y=-32 your final step is to divide both sides 8 that leaves you with -4 which is the answer.
Divide .98 by 3 1/2. 3 1/2 in decimal form is 3.5 so .98 ÷ 3.5 = .28
So one pound of bananas would cost <span>$0.28</span>