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2 years ago

One spring day, Zoey noted the time of day and the temperature, in degrees

Mathematics

1 answer:

Cloud [144]2 years ago

5 0

Answer:

2 hours

Step-by-step explanation:

Each square=1 hour

2 squares= 2 hours

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If a1 = 9 and and an-1 - 5 then find the value of a6.

SCORPION-xisa [38]

Answer:

a1 = 6 and an = an-1 - 5

a2 = a2-1 - 5 = a1 - 5 = 1

a3 = a3-1 - 5 = a2 - 5 = -4, etc

Step-by-step explanation:

8 0

2 years ago

Jackson used the process of completing the square to solve the equation 2x2−12x=−6.

Nikolay [14]

Answer:

$x=3-\sqrt{6},x=3+\sqrt{6}$

Step-by-step explanation:

we are given equation as

$2x^2-12x=-6$

Since, we have to solve it by using complete square

so, firstly we will complete square

and then we can solve for x

step-1:

Factor 2 from both sides

$2(x^2-6x)=-3\times 2$

step-2:

Simplify it

$x^2-6x=-3$

step-3:

Add both sides 3^2

$x^2-6x+3^2=-3+3^2$

now, we can complete square

$(x-3)^2=6$

step-4:

Take sqrt both sides

$(x-3)=-\sqrt{6},(x-3)=\sqrt{6}$

step-5:

Add both sides by 3

we get

$x=3-\sqrt{6},x=3+\sqrt{6}$

3 0

2 years ago

Mary sells to her father, robert, her shares in a corp for $55,000. the shares cost mary $80,000. how much loss may mary claim f

OverLord2011 [107]

Mary Purchase shares = $80,000
Mary Sells shares = $55,000

Loss she can claim for = $80,000 - $55,000
= $ 25,000

6 0

2 years ago

8x+2 what is the value of x?

spayn [35]

Answer:

you can't tell

Step-by-step explanation:

we don't know what x is equal to because there is no equivalent. x here can equal anything.

4 0

2 years ago

Read 2 more answers

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

2 years ago