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Brut [27]
3 years ago
10

One spring day, Zoey noted the time of day and the temperature, in degrees

Mathematics
1 answer:
Cloud [144]3 years ago
5 0

Answer:

2 hours

Step-by-step explanation:

Each square=1 hour

2 squares= 2 hours

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7
MrRissso [65]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Which integer is closest to 0 on the number line?
IrinaVladis [17]

An integer is close to zero if it is "small".

By small, we mean that it is small in absolute value. In fact, for any given distance d, there are two integers that are d units away from zero: d and -d.

So, for example, -6 is close to zero than 8, because -6 is six units away from zero, while 8 is eight units away from zero.

So, the answer is B, -8, because it is 8 units away from zero. The other options A, C and D are, respectively, 12, 10 and 14 units away from zero.

8 0
3 years ago
What is 2^5 in standard notation
elena-14-01-66 [18.8K]
2x2x2x2x2 is 2^5 in standard notation
8 0
3 years ago
Read 2 more answers
The volume of a cone is 3πx3 cubic units and its height is x units. Which expression represents the radius of the cone’s base, i
dalvyx [7]

Answer:

<em>r=3x</em>

Step-by-step explanation:

<u>The Volume of a Cone</u>

The volume of a cone of radius r and height h is:

\displaystyle V=\frac{1}{3}\pi hr^2

We are given the volume of a cone is

V=3\pi x^3

Equating:

\displaystyle \frac{1}{3}\pi hr^2=3\pi x^3

Multiplying by 3:

\pi hr^2=9\pi x^3

Simplifying by pi:

hr^2=9 x^3

Since h=x:

xr^2=9 x^3

Dividing by x:

r^2=9 x^2

Taking square roots:

r=\sqrt{9 x^2}=3x

Thus: r=3x

5 0
3 years ago
Read 2 more answers
Need help with the blanks
Crazy boy [7]
Answers: 
33. Angle R is 68 degrees
35. The fraction 21/2 or the decimal 10.5
36. Triangle ACG
37. Segment AB
38. The values are x = 6; y = 2
40. The value of x is x = 29
41. C) 108 degrees
42. The value of x is x = 70
43. The segment WY is 24 units long
------------------------------------------------------
Work Shown:
Problem 33) 
RS = ST, means that the vertex angle is at angle S
Angle S = 44
Angle R = x, angle T = x are the base angles
R+S+T = 180
x+44+x = 180
2x+44 = 180
2x+44-44 = 180-44
2x = 136
2x/2 = 136/2
x = 68
So angle R is 68 degrees
-----------------
Problem 35) 
Angle A = angle H
Angle B = angle I
Angle C = angle J
A = 97
B = 4x+4
C = J = 37
A+B+C = 180
97+4x+4+37 = 180
4x+138 = 180
4x+138-138 = 180-138
4x = 42
4x/4 = 42/4
x = 21/2
x = 10.5
-----------------
Problem 36) 
GD is the median of triangle ACG. It stretches from the vertex G to point D. Point D is the midpoint of segment AC
-----------------
Problem 37)
Segment AB is an altitude of triangle ACG. It is perpendicular to line CG (extend out segment CG) and it goes through vertex A.
-----------------
Problem 38) 
triangle LMN = triangle PQR
LM = PQ
MN = QR
LN = PR
Since LM = PQ, we can say 2x+3 = 5x-15. Let's solve for x
2x+3 = 5x-15
2x-5x = -15-3
-3x = -18
x = -18/(-3)
x = 6
Similarly, MN = QR, so 9 = 3y+3
Solve for y
9 = 3y+3
3y+3 = 9
3y+3-3 = 9-3
3y = 6
3y/3 = 6/3
y = 2
-----------------
Problem 40) 
The remote interior angles (2x and 21) add up to the exterior angle (3x-8)
2x+21 = 3x-8
2x-3x = -8-21
-x = -29
x = 29
-----------------
Problem 41) 
For any quadrilateral, the four angles always add to 360 degrees
J+K+L+M = 360
3x+45+2x+45 = 360
5x+90 = 360
5x+90-90 = 360-90
5x = 270
5x/5 = 270/5
x = 54
Use this to find L
L = 2x
L = 2*54
L = 108
-----------------
Problem 42) 
The adjacent or consecutive angles are supplementary. They add to 180 degrees
K+N = 180
2x+40 = 180
2x+40-40 = 180-40
2x = 140
2x/2 = 140/2
x = 70
-----------------
Problem 43) 
All sides of the rhombus are congruent, so WX = WZ.
Triangle WPZ is a right triangle (right angle at point P).
Use the pythagorean theorem to find PW
a^2+b^2 = c^2
(PW)^2+(PZ)^2 = (WZ)^2
(PW)^2+256 = 400
(PW)^2+256-256 = 400-256
(PW)^2 = 144
PW = sqrt(144)
PW = 12
WY = 2*PW
WY = 2*12
WY = 24
3 0
3 years ago
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