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atroni [7]
3 years ago
9

Mr. Percuoco is working the fish bowl toss. He used 13.6 gallons of water to fill 40 fish bowls. If he put an equal amount of wa

ter in each one, how many gallons of water are in each fish bowl?
Mathematics
1 answer:
nika2105 [10]3 years ago
4 0

Answer:

0.34 gallons of water

Step-by-step explanation:

Mr Percuoco is working the fish bowl toss

He used 13.6 gallons of water to fill 40 fish bowls

Therefore the gallons of water in each fish bowl can be calculated as follows

= 13.6/40

= 0.34

Hence there are 0.34 gallons of water in each fish bowl

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Answer:

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3 years ago
Read 2 more answers
Raymond wants to make a box that has a volume of 360 cubic inches. He wants the height to be 10 inches and the other two dimensi
Aleks [24]
V=LWH
h=10
V=360

360=LW10
divide both sides by 10
36=LW
try some values
ok so if we get L=1 and W=36, that is the same box as L=36 and W=1
so
L,W
36,1
18,2
12,3
9,4
6,6

5 of them

answer is 5 different boxes
dunno what the 'compare volume' is
8 0
3 years ago
Let x be a random variable that represents hemoglobin count (hc) in grams per 100 milliliters of whole blood. then x has a distr
Zolol [24]
<span>Answer: Calculating the t test statistic t = (xbar - mu)/(s/sqrt(n)) t = (4.40-4.66)/(0.28/sqrt(6)) t = -2.27452618972722 t = -2.275 The t test statistic is approximately -2.275</span>
4 0
3 years ago
) a, p and d are n×n matrices. check the true statements below:
BigorU [14]
A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).

b. True. Suppose \mathbf P is the matrix of the eigenvectors of \mathbf A, and \mathbf D is the diagonal matrix of the eigenvalues of \mathbf A:


\mathbf P=\begin{bmatrix}\mathbf v_1&\cdots&\mathbf v_n\end{bmatrix}

\mathbf D=\begin{bmatrix}\lambda_1&&\\&\ddots&\\&&\lambda_n\end{bmatrix}

Then

\mathbf{AP}=\begin{bmatrix}\mathbf{Av}_1&\cdots&\mathbf{Av}_n\end{bmatrix}=\begin{bmatrix}\lambda_1\mathbf v_1&\cdots&\lambda_n\mathbf v_n\end{bmatrix}=\mathbf{PD}

In other words, the columns of \mathbf{AP} are \mathbf{Av}_i, which are identically \lambda_i\mathbf v_i, and these are the columns of \mathbf{PD}.

c. False. A counterexample is the matrix

\begin{bmatrix}1&1\\0&1\end{bmatrix}

which is nonsingular, but it has only one eigenvalue.

d. False. Consider the matrix

\begin{bmatrix}0&1\\0&0\end{bmatrix}

with eigenvalue \lambda=0 and eigenvector \begin{bmatrix}k&0\end{bmatrix}^\top, where k\in\mathbb R. But the matrix can't be diagonalized.
7 0
3 years ago
find the number of terms in an AP given that its first and last terms are 13 and - 23 respectively and that its common differenc
Leokris [45]

Answer:

<u>There are 17 terms in the sequence</u>

Step-by-step explanation:

<u>Arithmetic Sequence </u>

An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:

a_n=a_1+(n-1)r

Where an is the nth term, a1 is the first term, and r is the common difference.

In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:

\displaystyle n=1+\frac{a_n-a_1}{r}

We need to express r as an improper or proper fraction:

\displaystyle r=-2\frac{1}{4}=-2-\frac{1}{4}=-\frac{9}{4}

Substituting:

\displaystyle n=1+\frac{-23-13}{-\frac{9}{4}}

\displaystyle n=1+\frac{-36}{-\frac{9}{4}}

\displaystyle n=1+36*\frac{4}{9}=17

n=17

There are 17 terms in the sequence

5 0
3 years ago
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