Question

How many roots does -2x^2-8=0 have​

Answer 1

Answer: two

Step-by-step explanation:

Factor out the equation:

-2($x^{2}$ + 4) = 0

-2 cannot equal zero, so that means $x^{2}$  - 4 will have to equal to zero in order to get zero as a product

$x^{2}$ - 4 = 0

Factor the equation to get:

(x+2)(x-2) = 0

x = 2, x = -2

The equation has two roots