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3 years ago

What is the purpose of simultaneous equations?

Mathematics

1 answer:

sveta [45]3 years ago

5 0

Answer:

a set of two or more equations, each containing two or more variables whose values can simultaneously satisfy both or all the equations in the set, the number of variables being equal to or less than the number of equations in the set.

Step-by-step explanation:

It works because of two properties of equations: Multiplying (or dividing) the expression on each side by the same number does not alter the equation. Adding two equations produces another valid equation: e.g. 2x = x + 10 (x = 10) and x − 3 = 7 (x also = 10).

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When a number is decreased by 47%, the result is 20. What is the original number

Digiron [165]

Answer:

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3 years ago

What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *

kvasek [131]

Given:

The function is:

$f(x)=350(1-0.12)^x$

To find:

The initial value of the function.

Solution:

We have,

$f(x)=350(1-0.12)^x$

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

$f(0)=350(1-0.12)^0$

$f(0)=350(0.88)^0$

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

$f(0)=350(1)$

$f(0)=350$

Therefore, the initial value of the function is 350.

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3 years ago

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expeople1 [14]

Answer:

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Step-by-step explanation:

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2 years ago

Question 2 of 10

ratelena [41]

Answer:

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Step-by-step explanation:

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3 years ago

There are x number of students at helms. If the number of students increases by 7.8% each year, how many students will be there

vodomira [7]

There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x

<h3><u>Solution:</u></h3>

Given, There are "x" number of students at helms.

The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x

Number of students in next year = number of students in present year + increased number of students.

$\begin{array}{l}{\text { Number of students in next year }=x+7.8 \% \text { of } x} \\\\ {\text { Number of students in next year }=x\left(1+\frac{7.8}{100}\right)} \\\\ {\text { Number of students in next year }=x(1+0.078)=1.078 x}\end{array}$

Thus there will be 1.078x students in next year

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3 years ago