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babymother [125]
3 years ago
13

Arrange the pennies into a complete rectangular array and then into a different rectangular array that has a reminder of 1

Mathematics
1 answer:
Inessa [10]3 years ago
4 0
I'm guessing the answer would be 141 pennies in a rectangular array I think I'm right but i might be wrong
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Compete the square to determine minum or maxuim value of function define by -x2+10x+5
HACTEHA [7]

Answer:

maximum value y = 30

Step-by-step explanation:

Given

- x² + 10x + 5

To complete the square the coefficient of the x² term must be 1

factor out - 1

= - (x² - 10x) + 5

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² - 10x

= - (x² + 2(- 5)x + 25 - 25) + 5

= - (x - 5)² + 25 + 5

= - (x - 5)² + 30 ← in vertex form

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Hence vertex = (5, 30)

The max/ min occurs at the vertex

Since a < 0 then vertex is a maximum

Hence maximum value is y = 30

3 0
3 years ago
How do I solve 34 x 17 using an area model
givi [52]
Multiplying 34x 17 and you will get answer
4 0
3 years ago
PLEASE HELP PLEASE PLEASE
snow_lady [41]
A i did this and i got a good grade
6 0
2 years ago
Read 2 more answers
How old am i if 400 reduced by 4 times my age is 144
Airida [17]

Answer:

400 divied by 4 is 144

so ur 14?

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Help! Thanks!!!!!!!!!
san4es73 [151]

1)

∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰

AB = 370 m

AC = 510 m

To find BC we can use cosine law.

a² = b² + c² -2bc*cos A

|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)

|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =

|BC| ≈ 553 m


2)

To find ∠ACB, we are going to use law of sine.

sin(∠BAC)/|BC| = sin(∠ACB)/|AB|

sin(76⁰)/553 m = sin(∠ACB)/370 m

sin(∠ACB)=(370*sin(76⁰))/553 =0.6492

∠ACB = 40.48⁰≈ 40⁰


3)

∠BAC = 76⁰

∠ACB = 40⁰

∠CBA = 180-(76+40) = 64⁰


Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰


4)

Shortest distance from A to BC is height (h) from A to BC.


We know that area of the triangle

A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).

Also, area the same triangle

A= (1/2)|BC|*h = (1/2)*553*h.


So, we can write

(1/2)*370*510*sin(76⁰) =(1/2)*553*h

370*510*sin(76⁰) =553*h

h= 370*510*sin(76⁰) / 553= 331 m

h=331 m


4 0
3 years ago
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