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3 years ago

How do I explain this?

Mathematics

1 answer:

dybincka [34]3 years ago

5 0

Answer:

Step-by-step explanation:

To do this, we have to prove that ∠1=∠5. We can do this using the corresponding angles theorem, which states that these two angles are congruent. Since ∠G=∠1, we can say ∠G=∠1=∠5, and as this, ∠G=∠5

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¿Cómo las razones de seno y cos<br>eno son semejantes?

Sauron [17]

Las razones de los lados de un triángulo rectángulo se llaman razones trigonométricas.

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3 years ago

The library is 1.75 miles directly north of the school. The park is 0.6 miles directly south of the school. How far is the libra

kumpel [21]

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3 years ago

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What is 10(n−2p+2) because i dont know the answer

Zigmanuir [339]

10n - 20p + 20

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3 years ago

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X - 5y = 10; (0, -2) Group of answer choices no yes

mr Goodwill [35]

Yes, this linear equation is correct on point (0,-2).

Given that:

The linear equation

x - 5y = 10;

The point

(0, -2)

To find

We have to prove LHS = RHS

So, according to the question

We have,

The linear equation,

x - 5y = 10; and point is (0,-2)

From equation,

x - 5y = 10

Take the left part of given linear equation,

LHS = x - 5y

Now, putting the values, x = 0 and y = -2.

Then, we will be get.

= x - 5y

= (0) - 5 ×(-2)

= - 5 × -2

= 10.

So, we can say that

LHS = RHS.

Where,

LHS = Left Hand Side.

RHS = Right Hand Side.

We can solve that linear equation in other way,

When we put x = 0, we get y = -2.

So, if we put x = 1, we get y = -9/5.

Similarly, if x = 2, then y = -8/5.

Now, we can say that points (0,-2), (1,-9/5) and (2,-8/5) are lie in the linear equation x - 5y = 10.

To learn more about linear equation, please click on the link;

brainly.com/question/13738061

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1 year ago

In arithmetic sequence tn find: S10, if t2=5 and t8=15

makkiz [27]

Given:

$\bold{t_2=5}\\\\\bold{t_8=15}\\\\$

To find:

$\bold{T_n=?}\\\\\bold{S_{10}=?}$

Solution:

$\to \bold{t_2=5}\\\\ \bold{a+d=5} \\\\ \bold{a=5-d} ................(i)\\\\ \to \bold{t_8=15}\\\\ \bold{a+ 7d=15}.................(ii)\\\\$

Putting the equation (i) value into equation (ii):

$\to \bold{5-d+7d=15}\\\\\to \bold{5+6d=15}\\\\\to \bold{6d=15-5}\\\\\to \bold{6d=10}\\\\\to \bold{d=\frac{10}{6}}\\\\\to \bold{d=\frac{5}{3}}\\\\$

Putting the value of (d) into equation (i):

$\to \bold{a=5-\frac{5}{3}}\\\\\to \bold{a=\frac{15-5}{3}}\\\\\to \bold{a=\frac{10}{3}}\\\\$

Calculating the $\bold{t_n :}$

$\to \bold{t_n=a+(n-1)d}\\\\\to \bold{t_n=\frac{10}{3}+(n-1)\frac{5}{3}}\\\\\to \bold{t_n=\frac{10}{3}+\frac{5}{3}n-\frac{5}{3}}\\\\\to \bold{t_n=\frac{10}{3}-\frac{5}{3} +\frac{5}{3}n}\\\\\to \bold{t_n=\frac{10-5}{3} +\frac{5}{3}n}\\\\\to \bold{t_n=\frac{5}{3} +\frac{5}{3}n}\\\\ \to \bold{t_n=\frac{5}{3}(1+n)}\\\\$

Formula:

$\bold{S_n = \frac{n}{2}[2a + (n - 1)d ] }\\$

Calculating the $\bold{S_{10}} :$

$\to \bold{S_{10} = \frac{10}{2}[2\frac{10}{3} + (10- 1)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + (9)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 9 \times \frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 3\times 5 ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 15 ] }\\\\\to \bold{S_{10} = 5[\frac{20+ 45}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{65}{3} ] }\\\\\to \bold{S_{10} = 5 \times \frac{65}{3} }\\\\\to \bold{S_{10} = \frac{325}{3} }\\\\\to \bold{S_{10} =108.33 }$

Therefore, the final answer is " $\bold{\frac{5}{3}(1+n)\ and\ 108.33}$ "

Learn more:

brainly.com/question/11853909

7 0

3 years ago

How do I explain this?​

How do I explain this?