PLEASE HELP URGENT!!! Devon can take one of three different buses to and from work (bus A, B, or C). He randomly catches one bus
in the morning and another one on the way home. This table lists the sample space of outcomes. Afternoon A B C Morning A AA AB AC B BA BB BC C CA CB CC In the event AB, Devon rides the A bus in the morning and the B bus in the afternoon. Which outcome would be included in the event "never rides bus B"? A. BB B. BA C. CB D. CA
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term So... f(x)=mx+b m=common difference b=starting point f(11)=125=11m+b - f(1)=5=1m+b -------- 120=10m Divide both sides by 10 12=m Your common difference is 12.
