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sergejj [24]
3 years ago
10

Rewrite the following using exponents. 5*5*5*5*5*5 O 25 (5) * (6) 056

Mathematics
1 answer:
anygoal [31]3 years ago
7 0
If there are six 5’s times each other then you would exponent 5^6

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Three hermit crabs at a pet store cost $ 21.75 . If each hermit crab, h , costs the same amount, which equation can be used to f
bixtya [17]

Answer:

Step-by-step explanation:

$21.75/(3 crabs) = $7.25/crab

5 0
3 years ago
Find the total cost of $52 shoes; 2.9%tax
MAVERICK [17]
Tax is:
$52* (2.9/100)= $1.51

$52+ $1.51= $53.51

The total cost (including tax) is $53.51~
4 0
3 years ago
The probability of flu symptoms for a person not receiving any treatment is 0.038. In a clinical trial of a common drug used to
alexgriva [62]

Answer:

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 1164, p = 0.038

So

\mu = E(X) = np = 1164*0.038 = 44.232

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = 6.5231

Estimate the probability that at least 47 people experience flu symptoms.

Using continuity correction, this is P(X \geq 47 - 0.5) = P(X \geq 46.5), which is 1 subtracted by the pvalue of Z when X = 46.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.5 - 44.232}{6.5231}

Z = 0.35

Z = 0.35 has a 0.6368

1 - 0.6368 = 0.3632

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

6 0
3 years ago
Please help, I would appreciate it a lot
AleksAgata [21]

Answer:

Sry, Can't help.

It's soo hard!!

8 0
3 years ago
14. Team 8A is selling snacks at the football game to raise money for a field trip. They are selling popcorn for $2.50 and pretz
Mamont248 [21]

Answer:

  • 40 popcorns and 90 pretzels sold.

============

Let the number of popcorns is x and pretzels is y.

Set up equations:

  • x + y = 130
  • 2.5x + 2y = 280

Solve by elimination, multiply the first equation by 2 and subtract from the second equation:

  • 2.5x + 2y - 2x - 2y = 280 - 2*130
  • 0.5x = 280 - 260
  • 0.5x = 20
  • x = 20/0.5
  • x = 40

Find y:

  • 40 + y = 130
  • y = 130 - 40
  • y = 90

5 0
2 years ago
Read 2 more answers
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