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Veseljchak [2.6K]

3 years ago

14

4 over 7 divided by 13 over 28

2 answers:

hammer [34]3 years ago

6 0

$\bf \cfrac{4}{7}\div \cfrac{13}{28}\implies \cfrac{4}{~~\begin{matrix} 7\\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{\stackrel{4}{~~\begin{matrix} 28 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{13}\implies \cfrac{16}{13}\implies 1\frac{3}{13}$

Galina-37 [17]3 years ago

5 0

Answer:

16/13

Step-by-step explanation:

Use a calculator lol

Can I have brainliest please

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9. Plot the points A (-2,3), B(2,-3), C(2,3) ,D(-2,3) join the points and find the distance between each point.

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Answer:

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Step-by-step explanation:

Coordinates of A =(-2,3)

Coordinates of B = (2,-3)

Coordinates of C = (2,3)

Coordinates of D =(-2,-3)

Distance formula : $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$A=(x_1,y_1)=(-2,3)\\B=(x_2,y_2)=(2,-3)\\AB = \sqrt{(2+2)^2+(-3-3)^2}$

AB=7.21 unit

$B=(x_1,y_1)=(2,-3)\\C=(x_2,y_2)=(2,3)\\BC=\sqrt{(2-2)^2+(3+3)^2}$

BC=6

$C=(x_1,y_1)=(2,3)\\D=(x_2,y_2)=(-2,-3)\\CD=\sqrt{(-2-2)^2+(-3-3)^2}$

CD=7.21

$A=(x_1,y_1)=(-2,3)\\D=(x_2,y_2)=(-2,-3)\\AD=\sqrt{(-2+2)^2+(-3-3)^2}$

AD=6

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$AC=\sqrt{(2+2)^2+(3-3)^2}$

AC=4

$B=(x_1,y_1)=(2,-3)\\D=(x_2,y_2)=(-2,-3)$

BD= $\sqrt{(-2-2)^2+(-3+3)^2}$

BD=4

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