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galben [10]
3 years ago
9

John is trying to drain a swimming pool. He has two pumps, but he can only use one at a time. He knows that the time a pump take

s to drain the pool varies inversely with the power in watts of the pump. His old pump is a 40 watt pump, and it can drain the pool in 5 hours. How long would the job take if he uses his new 100 watt pump?
Mathematics
1 answer:
xeze [42]3 years ago
8 0
What do you mean this sentence?
the time a pump takes to drain the pool varies inversely with the power in watts of the pump,
The meaning would be : if we have a power in watts greater the time to drag the pool will be less because the relation between power and time is inverse.  

40 watts--------------5 hours) 
100 watts------------  x

because the relation between power and time is inverse, we multiply directly.
40 watts(5 hours)=100 watts x
x=(200 watts hours) / 100 watts=2 hours.

Answer: the time would be 2 hours.   (the new pump is faster)
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Answer:

x = (-29)/5

Step-by-step explanation:

Solve for x:

(2 (x - 5))/3 = (3 (x + 1))/2

Multiply both sides by 6:

(6×2 (x - 5))/3 = (6×3 (x + 1))/2

6/3 = (3×2)/3 = 2:

2×2 (x - 5) = (6×3 (x + 1))/2

6/2 = (2×3)/2 = 3:

2×2 (x - 5) = 3×3 (x + 1)

2×2 = 4:

4 (x - 5) = 3×3 (x + 1)

3×3 = 9:

4 (x - 5) = 9 (x + 1)

Expand out terms of the left hand side:

4 x - 20 = 9 (x + 1)

Expand out terms of the right hand side:

4 x - 20 = 9 x + 9

Subtract 9 x from both sides:

(4 x - 9 x) - 20 = (9 x - 9 x) + 9

4 x - 9 x = -5 x:

-5 x - 20 = (9 x - 9 x) + 9

9 x - 9 x = 0:

-5 x - 20 = 9

Add 20 to both sides:

(20 - 20) - 5 x = 20 + 9

20 - 20 = 0:

-5 x = 9 + 20

9 + 20 = 29:

-5 x = 29

Divide both sides of -5 x = 29 by -5:

(-5 x)/(-5) = 29/(-5)

(-5)/(-5) = 1:

x = 29/(-5)

Multiply numerator and denominator of 29/(-5) by -1:

Answer: x = (-29)/5

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