Answer:
The formula to find a circle's area π (radius)2 usually expressed as π⋅r2 where r is the radius of a circle. The area of a circle is all the space inside a circle's circumference.
Step-by-step explanation:
Step-by-step explanation:
At first we can find AC
then we can find m<A and m< C
or, m<C and then m< A
m<B is already given in the question so there is no need of finding it.
The radicand of a quadratic is b^2-4ac.
If it is greater than zero, there are two real solutions
If it is equal to zero, there is one real solution
If it is less than zero, there are no real solutions (though there are two imaginary solutions)
In this case the discriminant is 256-2160 so it is less than zero.
Therefore there are no real solutions, though there are two imaginary solutions, specifically (16±i√-1904)/18
Answer:
x = (c+a)/2
y = (c-a)/2
Step-by-step explanation:
x+y=c
x-y=a
Add together to eliminate y
x+y=c
x-y=a
--------------
2x = c+a
Divide by 2
2x/2 =(c+a)/2
x = (c+a)/2
Multiply the second equation by -1
-x+y =-a
Add the first equation
x+y =c
-x+y=-a
-----------------
2y = c-a
Divide by 2
2y/2= (c-a)/2
y = (c-a)/2
