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3 years ago

FREE BRAINLY!!! if you answer correctly ill give you brainly :) (40pts total)

Mathematics

2 answers:

tiny-mole [99]3 years ago

6 0

c=0

Option 4 is correct

Hope it helps you

Mark me as brainliest

Cloud [144]3 years ago

5 0

Answer:

c=0

Step-by-step explanation:

option 4, 5(2c-3)=3(3c-5)==== c=0

Hope this helps! :D

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(-4, 8) and (6, 2). Slope

Setler79 [48]

Answer:

In order to go from the first point to the second, we need to rise from 4 to 7, i.e. by 3. We also need to run from -4 to -2, i.e. by 2. Therefore the slope is 32 .

Step-by-step explanation:

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2 years ago

You have a pan with a radius of 16 centimeters. if the cooking instructions say to cover the entire bottom of the pan with butte

Leno4ka [110]

Radius of the pan = 16cm

Formula for area of circle:

$\boxed { \boxed { \text {Area of a circle =} \pi r^2}}$

Find the area of the pan:

$\text {Area of the pan =} \pi (16)^2 = 804.25 \ cm^2$

$\boxed { \boxed {\text {Answer : The butter must cover 804.25 cm}^2}}$

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3 years ago

What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9

skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let $u^2=x^4\\u = x^2$

Subbing in:

$9u^2-2u-7=0$

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:

$9u^2-9u+7u-7=0$

Group together in groups of 2:

$(9u^2-9u)+(7u-7)=0$

Now factor out what's common within each set of parenthesis:

$9u(u-1)+7(u-1)=0$

We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:

$(u-1)(9u+7)=0$

Remember that $u=x^2$

so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.

$(x^2-1)(9x^2+7)=0$

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring $(x^2-1)$ gives us that x = 1 and -1. The other set is a bit more tricky. If