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sesenic [268]
3 years ago
5

Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0
<h2>Question :</h2>

<em>Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)</em>

<h2>Answer :</h2>

<em>y = -3/2x - 4 </em>

<h2>Explanation :</h2>

y = mx + c

*m = gradien

•>looking for gradients

y=2/3x+9

m1 = 2/3

m2 = -3/2

•>line equation (-6,5)

y - y1 = m(x - x1)

y - 5 = -3/2(x - (-6))

y - 5 = -3/2(x + 6)

y - 5 = -3/2 - 9

y = -3/2x - 9 + 5

y = -3/2x - 4

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Step-by-step explanation:

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Geometry 8.6.3 - Equations of Parallel and Perpendicular Lines and Proofs
Pepsi [2]

Option B: \frac{1}{25}

<u>Solution:</u>

<u>Slope of the perpendicular lines:</u>

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$m_1=\frac{-1}{ m_2}

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If two lines are parallel then they have the same slope.

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Using slope of the parallel lines definition,

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