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Marina CMI [18]
3 years ago
14

Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs

in simplest form.
Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

AB

AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}

AB \approx 7.616

BC

BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}

BC \approx 6.325

AC

AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}

AC \approx 5.831

Now we determine the area of the triangle by Heron's formula:

A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)} (1)

s = \frac{AB+BC + AC}{2} (2)

Where:

A - Area of the triangle.

s - Semiparameter.

If we know that AB \approx 7.616, BC \approx 6.325 and AC \approx 5.831, then the area of the triangle is:

s \approx 9.886

A = 18

The area of the triangle is 18 square units.

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