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Kazeer [188]
3 years ago
11

How do i solve for this?

Mathematics
1 answer:
dem82 [27]3 years ago
4 0

Answer:

Step-by-step explanation:

So you know the coords for the angle which is (1, 4).

Another coord might be (2, 5) or (0,3)

So we can find the slope

rise/run=1/1

so m=1

Sub in coords like (1,4) to find y-int

y=mx+b

4=1(1)+b

b=3

Thus y=x+3

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You need to isolate the variable my dividing each side by factors that don’t contain the variable
x=-5
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Ordered pair for the point
kupik [55]

Answer:

Step-by-step explanation:

(4, -3)

4 0
3 years ago
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Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra
Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize x^2-\frac13 as yet another difference of squares:

x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)

And if you're working over the field of complex numbers, you can go even further. For instance,

x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)

But I think you'd be fine stopping at the first result,

x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}

6 0
3 years ago
Pls help need it for tommorow​
ANEK [815]

Step-by-step explanation:

\frac{3}{10 }  = .3

7 0
3 years ago
Read 2 more answers
Find the area of the composite figure.
Viefleur [7K]

The area of the composite figure from the image attached is 112.5 units²

<h3>What is the area of a composite figure?</h3>

The area of a composite figure refers to the sum total of all the areas of the shapes in that composite figure. This can be done by first identifying the shapes in that composite figure, then finding each area, followed by the addition of all the areas to determine the area of the composite figure.

From the given figure; we can break it down into:

  • A parallelogram
  • A rectangle
  • A triangle

The area of a parallelogram = b × h

where;

  • b & h refers to the length of the two opposite diagonal lines.

The area of a parallelogram =  9 × 6

The area of a parallelogram = 54 units²

The area of a rectangle = Length × breadth

The area of a rectangle = (9 × 3) units²

The area of a rectangle = 27 units²

The area of the triangle \mathbf{=\dfrac{1}{2}\times b \times h}

where;

  • Base = b
  • Height = h

The area of the triangle \mathbf{=\dfrac{1}{2}\times b \times h}

The area of the triangle \mathbf{=\dfrac{1}{2}\times 9 \times 7}

The area of the triangle \mathbf{= 31.5 units^2}

Therefore, the area of the composite figure is:

= 54 + 27 + 31.5

= 112.5 units²

Learn more about composite figures here:

brainly.com/question/15981553

4 0
2 years ago
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