Given :
Weekly salary , S = $150.
Commission per car , C = $325.
To Find :
The the equation that models the weekly salary of a car salesman.
Solution :
We know it is a quadratic equation :
Let , the equation is , y = mx + c
Here, x is number of car sold in a week.
For x = 0 ( He will not get commission)
So , Salary is $150 = c .
For x = 1
Salary is $( 150 + 325 ) = $475 = m(1) + c
Therefore , m = $325 and c = $150.
Required linear equation is y = 325x + 150.
Hence, this is the required solution.
Answer:
Step-by-step explanation:it’s number 4
Answer:
(a) (6, 2)
Step-by-step explanation:
The system of equations has one of them in y= form, so it lends itself to solution by substitution.
__
Using the equation for y to substitute into the first equation, we have ...
2x -y = 10
2x -(-1/2x +5) = 10 . . . . . substitute for y
2x +1/2x -5 = 10 . . . . . eliminate parentheses
5/2x = 15 . . . . . . . . . add 5, collect terms
x = 6 . . . . . . . . . . . multiply by 2/5
Using the equation for y, we have ...
y = -1/2(6) +5 = -3 +5
y = 2
The solution is (x, y) = (6, 2).
Answer:
18÷n or 18a
Step-by-step explanation:
If a function has roots -1 and -5, it must be in the form

We can fix the coefficient a by imposing the passing through (0,-30):

So, the function is
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