All categories

3 years ago

Can someone please give me the answer

Mathematics

1 answer:

Serga [27]3 years ago

7 0

Answer:

#1 = 234

Step-by-step explanation:

You might be interested in

What 4.1555 rounded to the nearest tenth

Shkiper50 [21]

The answer is 4.2 because if the next digit is 5 or more it will round up

7 0

3 years ago

Read 2 more answers

Select all the expressions that are equivalent to .

olga55 [171]

Answer:

1. 9 - 10n = -1 + 1/10

2. 14 - 3n = 14 - 3n

3.14 - 21 = - 7⋅ (3n - 2)

4. (2-3n)⋅7 = Sorry i dont know

5. I HAVE NO IDEA SO SORRY

Step-by-step explanation:

5 0

3 years ago

6. Leon says he can find the sum of 30 + 67 without

Phoenix [80]

Answer:

You can just place the 7 instead of the 0 since if you add anything to 0 it is the number you added. then 3 and 6 make 9. so it is 97.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

10^6 times 10^5 as a power of ten - thanks !

Colt1911 [192]

Answer:

one hundred billion

Step-by-step explanation:

10^6 x 10^5 = 10^11

10^11 = 100,000,000,000 or one hundred billion

I hope that's what you meant ^-^

7 0

3 years ago

Solve the equation for x∈Z <br><br>-x² +8x -14 ≥ 0

kenny6666 [7]

$ax^2+bx+c=0\\\Delta=b^2-4ac\\if\ \Delta < 0\ then\ no\ solutions\\if\ \Delta=0\ then\ one\ solution:x=\frac{-b}{2a}\\if\ \Delta > 0\ then\ two\ solutions:x=\frac{-b\pm\sqrt\Delta}{2a}\\================================\\\\-x^2+8x-14\geq0\ \ \ \ |multiply\ both\ sides\ by\ (-1)\ \{change\ \geq\ on\ \leq\}\\\\x^2-8x+14\leq0\\\\a=1;\ b=-8;\ c=14\\\\\Delta=(-8)^2-4\cdot1\cdot14=64-56=8 > 0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2$

$x_1=\frac{-(-8)-2\sqrt2}{2\cdot1}=\frac{8-2\sqrt2}{2}=\frac{8}{2}-\frac{2\sqrt2}{2}=\boxed{4-\sqrt2}\\\\x_2=\frac{-(-8)+2\sqrt2}{2\cdot1}=\frac{8+2\sqrt2}{2}=\frac{8}{2}+\frac{2\sqrt2}{2}=\boxed{4+\sqrt2}\\\\============================$

$ax^2+bx+c=0\\\\if\ a > 0\ then\ the\ parabola\ o pen\ up\\if\ a < 0\ then\ the\ parabola\ o pen\ down\\========================\\\\a=1 > 0-therefore\ o pen\ up\ (look\ at\ the\ picture)\\\\===============================\\\\Answer:x\in\left$

$Solutions\ in\ \mathbb{Z}:\\\\\sqrt2\approx1.4\\\\threfore:4-\sqrt2\approx4-1.4=2.6\ and\ 4+\sqrt2\approx4+1.4=5.4\\\\look\ at\ the\ second\ picture:x=3\ or\ x=4\ or\ x=5\ (x\in\{3;\ 4;\ 5\})$

6 0

3 years ago

Read 2 more answers