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eduard
3 years ago
12

Billy bought Katie a present wrapped in this box. How much wrapping paper would He need to wrap the present in this box, PLEASE

HELP! WILL MARK BRAINLIEST

Mathematics
2 answers:
Setler [38]3 years ago
7 0

Answer:

284mm²

Step-by-step explanation:

S.A.= 2(lw) + 2(lh)+ 2(wh)

2[12.6(8)] + 2[12.6(2)] + 2[8(2)]

201.6 + 50.4 + 32

S.A.= 284mm²

evablogger [386]3 years ago
5 0

Answer:

B

Step-by-step explanation:

You need a top and bottom (same size)

You need a front and back (same size for them as well)

You need  a left and right covering.

Top and bottom = 2 * 12.6 * 8 = 201.6

Left Right = 2 * 8 * 2 =                  32.0

Front/Back= 2 * 2 * 12.6 =        <u>     50.4</u>

Total                                            284

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Two mechanics worked on a car. The first mechanic worked for 15
4vir4ik [10]

Answer:

First: $65

Second: $115

Step-by-step explanation:

We write equations for each part of this situation.

<u>The Total Charge</u>

Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.

<u>The Sum of the Rates</u>

Since the first's rate is a and the second is b, we can write a+b=180 since their sum is 180.

We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.

For a+b=180, rearrange to b=180-a and substitute into 15a+5b=1550.

15a + 5 (180-a)=1550

15a+900-5a=1550

10a+900-900=1550-900

10a=650

a=$65 was charged by the first mechanic.

We substitute to find the second mechanic's rate.

65+b=180

65-65+b=180-65

b= $115 was charged by the second mechanic

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