Answer:
The probability that a randomly selected adult is either overweight or obese is 0,688
Step-by-step explanation:
Probability that an american adult is overweight = 0,331
Probability that an american adult is obese = 0,357
Let's find the probability that an adult is either overweight or obese, that means both events are mutually exclusive. We are interested in the probability that just one event occurs, that probability is the sum of their individual probabilities
P(overweight ∪ obese) = P(overweight) + P(obese) = 0,331 + 0,357 = 0,688
Wouldnt the answer be D -|-(-4.2)|
Answer:
y = -1/2x + 4
Step-by-step explanation:
I got -1/2x because for every 2 spaces, the line goes down 1 (rise/run)
I got +4 because 4 is where x = 0, or the y intercept
