Median: 29
Range: 25
IQR: 14.5
Explanations:
**Median:**
(To find the median, we need to first order all the elements)
Ordered —> 15, 18, 18, 20, 23, 28, 30, 33, 33, 34, 38, 40
(Since there are an even number of elements, we need to add the two elements in the middle and divide by 2)
Median = (28 + 30)/2 = 58/2 = 29
**Range:**
(To find the range, you just have the subtract the smallest one from the largest)
Range = 40 - 15 = 25
**IQR:**
First half of elements —> 15, 18, 18, 20, 23, 28
Second half of elements —> 30, 33, 33, 34, 38, 40
Q1 (Quartile 1) = Median of first half = (18 + 20)/2 = 38/2 = 19
Q3 (Quartile 3) = Median of second half = (33 + 34)/2 = 67/2 = 33.5
IQR = Q3 - Q1 = 33.5 - 19 = 14.5
Answer:
1 is 1/2 5 is 2 1/2 and 7 would be 3 1/2
Step-by-step explanation:
Answer:
I hope you get it .............
Answer:
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Step-by-step explanation:
Answer:
A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution
Step-by-step explanation:
Given that there is a continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers
Since the pdf is rectangular in shape and total probability is one we can say all values in the interval would be equally likely
Say if the interval is (a,b) P(X) = p the same for all places
Since total probability is 1,
we get integral of P(X)=p(b-a) =1
Or p= 
this is nothing but a uniform distribution continuous defined in the interval
A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution