Answer:
65625/4(x^5)(y²)
Step-by-step explanation:
Using binomial expansion
Formula: (n k) (a^k)(b ^(n-k))
Where (n k) represents n combination of k (nCk)
From the question k = 5 (i.e. 5th term)
n = 7 (power of expression)
a = 5x
b = -y/2
....................
Solving nCk
n = 7
k = 5
nCk = 7C5
= 7!/(5!2!) ------ Expand Expression
=7 * 6 * 5! /(5! * 2*1)
= 7*6/2
= 21 ------
.........................
Solving (a^k) (b^(n-k))
a = 5x
b = -y/2
k = 5
n = 7
Substituting these values in the expression
(5x)^5 * (-y/2)^(7-5)
= (3125x^5) * (-y/2)²
= 3125x^5 * y²/4
= (3125x^5)(y²)/4
------------------------------------
Multiplying the two expression above
21 * (3125x^5)(y²)/4
= 65625/4(x^5)(y²)
3000 = p( 1 + .06/2)^(4 * 2)
<span>3000 = p(1.03)⁸ </span>
<span>p = 3000/ 1.03⁸ </span>
<span>p = 2368.2277029 </span>
<span>$2368.23 <-----</span>
Answer:
Step-by-step explanation:
(-2,2) ...x1 = -2 and y1 = 2
(4,6)..x2 = 4 and y2 = 6
midpoint formula :
m = ((x1 + x2) / 2 , (y1 + y2) / 2)
m = ((-2 + 4) / 2 , (2 + 6) / 2)
m = 2/2 , 8/2
m = (1,4) <===
-4,. 3
or. ±4/1,. ±2/1,. ±1/1,. ±4/3,. ±2/3,. ±1/3,.
4,080,499 rounded to the nearest thousand is 4,080,000.
