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NikAS [45]
4 years ago
13

The slope of a line through the points (-2, 4) and (6, b) is -

Formula1" title="\frac-{3}{4}" alt="\frac-{3}{4}" align="absmiddle" class="latex-formula"> What is the value of b? Explain your method for calculating b.
Mathematics
2 answers:
kiruha [24]4 years ago
8 0

Answer:

b = -2

Step-by-step explanation:

irina [24]4 years ago
3 0
<h3>Answer:  b = -2</h3>

==============================

Work Shown:

m = (y2-y1)/(x2-x1)

m = (b-4)/(6-(-2))

m = (b-4)/(6+2)

m = (b-4)/8

Set this equal to the slope -3/4 and solve for b

(b-4)/8 = -3/4

4*(b-4) = 8*(-3) ... cross multiply

4b-16 = -24

4b = -24+16 ... adding 16 to both sides

4b = -8

b = -8/4

b = -2

---------------------

Since b = -2, we can replace b with -2

That makes the point (6,b) turn into (6,-2)

Now apply the slope formula to (-2,4) and (6,-2). We should get -3/4 as a result

m = (y2-y1)/(x2-x1)

m = (-2-4)/(6-(-2))

m = (-2-4)/(6+2)

m = -6/8

m = -3/4

So everything works out.

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3 years ago
What is an equation of the line that passes through the points (0, -4) and (-4, 6)?
olganol [36]

Answer:

The equation of the line is.

y=-\frac{5}{2}x-4

Step-by-step explanation:

Given:

The given points are (0, -4) and (-4, 6)

The equation of the line passing through the points (x_{1},y_{1}) and (x_{2},y_{2}) is.

\frac{x-x_{1}}{x_{2}-x_{1}}=\frac{y-y_{1}}{y_{2}-y_{1}}

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The above equation is divided by 2 both sides.

2y=-5x-8

y=-\frac{5}{2}x-4

Therefore, the equation of the line that passes through the points (0, -4) and (-4, 6) is y=-\frac{5}{2}x-4

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Answer:

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