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3 years ago

What type of function can be used to model the scenario?

Mathematics

1 answer:

solmaris [256]3 years ago

5 0

Answer:

1. Exponential

2. Linear

Step-by-step explanation:

1. Exponential

Principal = 15000

Rate, r = 6.5% compounded annually

A = P(1 + r)^t

A = 15000(1 + 0.065)^t

A = 15000(1.065)^t

2. Linear

Let initial amount in bank = x

Amount added per week = 2

Number of weeks or period = t

A = x + 2t

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5\2,3 and 3\2,8 find the distance

pochemuha

Answer:

√26 ≈ 5.1 units

Step-by-step explanation:

√(x₂ - x₁)² + (y₂ - y₁)²

√(3/2 - 5/2)² + (8 - 3)²

√(-1)² + (5)²

√1 + 25

√26

4 0

4 years ago

The given line passes through the points (-4,-3) and (4,

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

first we gotta find the slope of the first line

(-4,-3),(4,1)

slope = (y2 - y1) / (x2 - x1) = (1- (-3) / (4 - (-4) = (1 + 3) / (4 + 4) = 4/8 = 1/2

so the slope is 1/2.....so we are looking for a line that is perpendicular....perpendicular lines have negative reciprocal slopes...all that means is flip the slope and change the sign....so the slope we need is :

1/2....flip it....2/1.....change the sign....-2.....we need a -2 slope

y - y1 = m(x - x1)

slope = -2

(-4,3)...x1 = -4 and y1 = 3

now sub

y - 3 = -2(x - (-4) =

y - 3 = -2(x + 4) <=====

6 0

3 years ago

Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam

Serjik [45]

Answer:

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that $n = 75$ and $\pi = \frac{44}{75} = 0.586$ .

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291$

The upper limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429$

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0

3 years ago

Looking at this shape, which line represents a Diameter? Р B. A 0 С

ahrayia [7]

Correct me if I’m wrong but I believe it to b

4 0

3 years ago

Read 2 more answers

Hank bought 5 CDs for $64.75. If each CD cost the same price, how much did each cost?

dem82 [27]

64.75/5= $12.96

you simply divide 64.75 by 5

6 0

3 years ago