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Alex
3 years ago
13

What is that first step in solving the equation 2x-1=3?

Mathematics
2 answers:
ddd [48]3 years ago
5 0

Answer:

subtract 1 then divide 2

Step-by-step explanation:

Crazy boy [7]3 years ago
5 0
+1 to both sides is step one
Then divide both sides by two to get x=2
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Which two whole numbers is √20 between?
Kay [80]

Answer:4 and 5

Step-by-step explanation:

√(20) is approximately 4.5 so it is between 4 and 5

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What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)?
rusak2 [61]

Answer:

The equation for the given line is y − 1 = 4(x + 3). Let us convert this equation in slope intercept form y= mx +b, where m is slope and b is the y-intercept. Thus, the slope of this line is 4.Now, we know that the slope of parallel lines are equal. Hence, the slope of the required line is same as the slope of the given line. Hence, the slope of the required line is m = 4It passes through the point (4,32).The point slope form of a line is given by Therefore the equation of the line is y = 4x+16,D is the correct option.

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3 years ago
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A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
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