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3 years ago

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If U is the set of all natural numbers less than 10, A is its subset containing all natural numbers less than 6 and B⊂U consists

of all natural numbers greater than 4 (and of course smaller than 10), draw Venn diagram showing these sets. List elements of sets A, B, their union, and their intersection.

1 answer:

RideAnS [48]3 years ago

3 0

You find it in the website that the girl just posted it’s a real website btw not a troll

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A police officer is chasing a purse-snatcher down a street. The thief starts 9 meters ahead of the officer and can run 20 meters

lions [1.4K]

Answer:

If you want them at the same exact point then since the theif is 9 steps ahead it

will take 3 seconds

Step-by-step explanation:

Robber:

<em>starts at 9</em>

<em>starts at 9add on 5 and you get 14</em>

<em>starts at 9add on 5 and you get 14add 5 more you get 19</em>

<em>starts at 9add on 5 and you get 14add 5 more you get 19and another 5 would give you 24</em>

Police:

<em>is</em><em> </em><em>at</em><em> </em><em>0</em><em> </em><em>meters</em><em> </em>

<em>add</em><em> </em><em>8</em><em> </em><em>any</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>8</em>

<em>add</em><em> </em><em>8</em><em> </em><em>more</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>1</em><em>6</em>

<em>and</em><em> </em><em>another</em><em> </em><em>8</em><em> </em><em>would</em><em> </em><em>get</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>2</em><em>4</em>

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3 years ago

The quotient of four times a number and six is eight.

Anna35 [415]

Answer:

Quotient = Divide

8 = 4x * 6

6 0

2 years ago

Read 2 more answers

What are whole number dimensions?

Sphinxa [80]

When you get to the point where the width is larger than the length, you can stop because you have exhausted all the possibilities. The greatest area will be the rectangle that is closer in to a square than any of the others.

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3 years ago

Read 2 more answers

Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.

____ [38]

Let $z=-\sqrt3+i$ . Then

$|z|=\sqrt{(-\sqrt3)^2+1^2}=2$

$z$ lies in the second quadrant, so

$\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6$

So we have

$z=2e^{i5\pi/6}$

and the fourth roots of $z$ are

$2^{1/4}e^{i(5\pi/6+k\pi)/4}$

where $k\in\{0,1,2,3\}$ . In particular, they are

$2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}$

$2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}$

$2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}$

$2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}$

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3 years ago

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

$\$180.55$

Step-by-step explanation:

step 1

<u><em>Simple interest</em></u>

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

<u><em>Interest compounded annually</em></u>

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

$A=2,250(1.04)^{10}$

$A=\$3,330.55$

step 3

Find the differences between the two final amounts

$A=\$3,330.55-\$3,150=\$180.55$

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3 years ago