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il63 [147K]
3 years ago
11

Phillip is rolling two number cubes. How many different ways can he roll the number cubes and get a sum of 6?

Mathematics
2 answers:
Verizon [17]3 years ago
8 0

Answer:

3

Step-by-step explanation:

qwelly [4]3 years ago
6 0

Answer:

3

Step-by-step explanation:

If the two number cubes are a standard six sided dice then the total of ways he can roll for the sum of 6 is 3

1+5 = 6

2+4 = 6

3+3 = 6

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What is the mode for the following set of data? 5,7,8,10,12,12
Volgvan

Answer:

12

Step-by-step explanation:

its the most common number

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3 years ago
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Marissa got an 85% on her math quiz. If she got 34 questions correct, know how many questions were on the quiz.
ikadub [295]

<u>Answer:</u> 40

<u>Reasoning:</u> 34/.85= 40

40x.85=34

8 0
3 years ago
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(3x^4y^5) ^ 3/7 in radical form
kobusy [5.1K]

The expression in radical form is (\sqrt[7]{3x^4y^5}) ^3

In order to express the given indices expression in radical form, we need to ensure there is a square root present in the resulting expression.

According to the law of indices,

a^{m/n} = \sqrt[n]{m}

Given the indices (3x^4y^5) ^ {3/7}

Comparing with the general formula, we will see that:

m = 3

n = 7

a = 3x^4y^5

Applying the law of indices:

(3x^4y^5) ^ {3/7} = (\sqrt[7]{3x^4y^5}) ^3

Hence the expression in radical form is (\sqrt[7]{3x^4y^5}) ^3

Learn more here: brainly.com/question/6755932

3 0
2 years ago
$5 box of cereal: 40% discount?
REY [17]
Uh sure what type of cereal?
4 0
3 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
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