The area of the space under the slide is 2.10 square meters
<h3>The vertical distance</h3>
The diagram in the question is added as an attachment
The vertical distance is represented by h.
So, we have:
sin(70) = h/2
Solve for h
h = 2 * sin(70)
Evaluate
h = 1.88 m
Hence, the vertical distance is 1.88 m
<h3>The length of the slide</h3>
This is calculated using
sin(40) = h/Slide
This gives
sin(40) = 1.88/Slide
Solve for Slide
Slide = 1.88/sin(40)
Evaluate
Slide = 2.92
Hence, the length of the slide is 2.92 m
<h3>The
area of the
space under the slide</h3>
This is calculated using:
A = 0.5 * h * slide * sin(∅)
Where
∅ = 90 - 40 = 50
So, we have:
A = 0.5 * 1.88 * 2.92 * sin(50)
Evaluate
A = 2.10
Hence, the area of the space under the slide is 2.10 square meters
Read more about triangles at:
brainly.com/question/11952845
#SPJ1
B.
Since he had to subtract 7 to get to -3, you would have to find the expression that would yield that answer.
Hope this helps!
I'll answer 3 of these questions.
For future notice, make sure to limit yourself to asking at most, 3 individual questions per question. :)
1) r/10+4=5
Subtract both sides by 4.
(r/10+4)-4=(5)-4
r/10=1
Multiply both sides by 10.
(r/10)*10=(1)*10
r=10
2) n/2+5=3
Subtract 5 from both sides.
(n/2+5)-5=(3)-5
n/2=-2
Multiply both sides by 2.
(n/2)*2=(-2)*2
n=-4
3) 3p-2=-29
Add 2 to both sides.
(3p-2)+2=(-29)+2
3p=-27
Divide both sides by 3.
(3p)/3=(-27)/3
p=-9
Hope this helps.
-Benjamin
So you want to know how much rolls can Rosa make with the dough, here's the answer:
First we notice that each roll takes 1/8 of dough, and then we make
into
.
Then we find, that we can make 30 rolls with the dough Rosa has!
Hope this helped! c:
Answer:
Option (4)
Step-by-step explanation:
D = {x| x is a whole number}
D = {1, 2, 3, 4..........}
E = {x | x is a perfect square between 1 and 9}
E = {4}
F = {x | x is an even number greater than 2 and less than 9}
F = {2, 4, 6, 8}
(E ∩ F) = Set of common numbers of E and F
= {4}
D ∩ (E ∩ F} = Set of common numbers in the sets of D and (E ∩ F)
= {4}
Therefore, Option (4) will be the answer.
